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Igoryamba
3 years ago
11

Simplify 2 to the 5th over 3 squared all raised to the 4th power.

Mathematics
1 answer:
son4ous [18]3 years ago
8 0
I think that would be C but idk tell me if im right
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An insurance company states that it settles 85% of all life insurance claims within 30 days. A consumer group asks the state ins
BlackZzzverrR [31]

Using the z-distribution, it is found that since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence that the proportion is below 85%, that is:

H_0: p \geq 0.85

At the alternative hypothesis, it is tested if there is enough evidence that the proportion is below 85%, that is:

H_0: p < 0.85

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

For this problem, the parameters are:

p = 0.85, n = 250, \overline{p} = \frac{203}{250} = 0.812

Hence the test statistic is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.812 - 0.85}{\sqrt{\frac{0.85(0.15)}{250}}}

z = -1.68

<h3>What is the p-value and the conclusion</h3>

Using a z-distribution calculator, with a left-tailed test, as we are testing if the proportion is less than a value, and z = -1.68, the p-value is of 0.0465.

Since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

More can be learned about the z-distribution at brainly.com/question/16313918

#SPJ1

4 0
1 year ago
Write an equation for the line described in standard form with x-intercept 4 and y-intercept 5
stealth61 [152]

Answer:

Equation( \frac{5}{4}) x  + y = 5 is in the standard dorm.

Step-by-step explanation:

Here, the x - intercept = 4 , so ( 4,0) is a point on the line.

and the y - intercept = 5, so ( 0,5) is a point on the line.

So, the slope of the equation is given as  =  \frac{y_2 - y_1}{x_2-x_1 }  = \frac{5 -0}{0-4}  = -\frac{5}{4}

Now, the SLOPE INTERCEPT FORM of an equation is :

y  = mx + b: here m  = slope and b =  y- intercept

or, y =-( \frac{5}{4}) x + 5

Now, standard form is Ax +By = C

So, the standard form is ( \frac{5}{4}) x  + y = 5

Hence, the above equation ( \frac{5}{4}) x  + y = 5

is in the standard dorm.

4 0
3 years ago
Find the area of the circle. Round to the nearest tenth. Use 3.14 or 22/7 for pie.
maks197457 [2]

Answer:

98.5 cm2

Step-by-step explanation:

6 0
3 years ago
Domain and range of the function f(x)= 7x^5<br> PLEASE HELP I LITERALLY CANT DO IT
sineoko [7]

Answer:

Domain: all real numbers

Range: all real numbers

Step-by-step explanation:

The domain is all x values, and the range is all y values.

<u><em>Domain:</em></u>

The domain is all real numbers except where the slope is undefined (a vertical line). In this case, no number makes the expression undefined, so the domain is:

all real numbers

<u><em>Interval notation:</em></u><em>  </em>(-∞,∞)

all negative numbers and positive numbers (all real numbers)

<em><u>Set-Builder Notation:</u></em> {x | x ∈ R }

<em><u>Range:</u></em>

The range is the set of all valid values. Graph the line and check. Since all values of y are valid, the range is:

all real numbers

<u><em>Interval notation:</em></u><em>  </em>(-∞,∞)

all negative numbers and positive numbers (all real numbers)

<em><u>Set-Builder Notation:</u></em> {x | x ∈ R }

:Done

3 0
2 years ago
The diameter of a circle is 6 km what is the circles area
tankabanditka [31]
The area of the circle will be 28.27 km.
3 0
3 years ago
Read 2 more answers
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