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Novosadov [1.4K]
3 years ago
11

. In one Ivy Tech region the number of students in Math 136 is 20% more than the number of students in Math 123. If there are 48

0 students in Math 136, how many students are in Math 123?
Mathematics
2 answers:
mash [69]3 years ago
5 0

Answer: 400

Step-by-step explanation:

Marat540 [252]3 years ago
3 0

Number of students in Math136 = 480

We are given that the number of students in Math136 is 20% more than the number of students in Math123. Let the number of students in Math123 be x. So we can set up the equation as:

Number of students in Math136 = 20% more than number of students in Math123

Number of students in Math136 = 20% more than x

480 = 20% more than x

480 = 20% of x + x

480 = 0.20x + x

480 = 1.20(x)

x = 480/1.20 = 400

This means, there are 400 students in Math123.

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Jenette rides her bike to the bus station where she barely makes it in time to catch the bus to work. She spends half an hour on
aleksklad [387]

Answer:

The rate of the bike is approximately 23.14 mph

The rate of the bus is approximately 62.14 mph

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The given parameters are;

The time Janette spends on her bike to get to bus station = Half an hour = 0.5 hours = 30 minutes

The time Janette spends on the bus on her way to work = Two-thirds of an hour = 2/3 hours

The speed of the bus = 39 mph + The speed with which Janet travels on her bike

The total distance from her home to her work = 40 miles

To answer the question, let the speed with which Janet travels on her bike in miles per hour = x = the rate of the bike

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The speed rate of the bus = 39 + x

Distance = Speed × Time

The distance Janet travels to the bus station = The speed with which Janet travels on her bike × The time Janette spends on her bike to get to bus station

The distance Janet travels to the bus station = x × 0.5 = 0.5·x

The distance travelled by the bus from the bus station to her work = The speed of the bus × The time Janette spends on the bus from the bus station to her place of work

∴The distance travelled by the bus from the bus station to her work = (39 + x) × 2/3 hours = 13 + 2/3·x

The total distance from her home to her work = 40 miles = The distance Janet travels to the bus station + The distance travelled by the bus from the bus station to her work

∴ The total distance from her home to her work = 40 miles = 0.5·x + 13 + 2/3·x

Which gives;

40 = 0.5·x + 13 + 2/3·x

40 = 7/6·x + 13

7/6·x = 40 - 13 = 27

7/6·x = 27

x = 27 × 6/7 ≈ 23.14 mph

The rate of the bike = x ≈ 23.14 mph

The rate of the bike ≈ 23.14 mph

The speed rate of the bus = 39 + x ≈ 39 + 23.14  ≈ 62.14 mph

The speed rate of the bus ≈ 62.14 mph.

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