What is Y= -8x+3 on a graph?, what’s the points ?

Mathematics

1 answer:

Brilliant_brown [7]4 years ago

6 0

Answer:

go on the y axis and go up to (0,3) that will be your first point then from there you go down 8 and right 1 so your point will be (-5,1)

Step-by-step explanation:

You might be interested in

Write the quadratic equation in general form and then choose the value of "b."

Ira Lisetskai [31]

First of all to transfer (2x - 1)(x + 6) = 0 into a form where we can plug it into the quadratic formula we need to use the FOIL method.

(2x - 1)(x + 6) = 0
 becomes
2x*x+2x*6+-1*x+-1*6
which simplifies to
2x^2 + 12x - x - 6
and then we add like terms to get
2x^2 + 11x - 6

now that it is in the correct form we can identify "a" "b" and "c" by following this form
ax^2 + bx + c
looking back at the equation we got earlier
2x^2 + 11x - 6

a=2,b=11,and c=-6

4 0

4 years ago

Read 2 more answers

Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)

Allisa [31]

Part A:

Given the function $f(x)=x+2\cos(x)$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow1-2\sin{x}=0 \\ \\ \Rightarrow2\sin{x}=1 \\ \\ \Rightarrow\sin{x}= \frac{1}{2} \\ \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}$

Using the second derivative test,

$f''(x)=-2cosx \\ \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732$

Since the second derivative gives a negative number, the given function has a maximum point at $x=\frac{\pi}{6}$ .

And the maximum point is given by:

$f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\ \\ =0.5236+2(0.8660)=0.5236+1.732 \\ \\ =\bold{2.256}$

i.e. $\left(\frac{\pi}{6},\ 2.256\right)$

Part B:

Given the function $f(x)=e^{-x}-e^{-2x}$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\ \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\ \\ \Rightarrow x=0.6931$

Using the second derivative test,

$f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\ \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\ \\ =-0.5$

Since the second derivative gives a negative number, the given function has a maximum point at $x=0.6931$ .

And the maximum point is given by:

$f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\ \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}$

i.e. (0.693, 0.25)

3 0

3 years ago

Which coordinate is the rule for the translation of f(x) to g(x)

labwork [276]

the coordinates of the vertex of the f(x) is (2 , -3) and when f(x) is converted to g(x) the coordinates of the vertex [ vertex of g(x) ] has become ( 7 , -7) when f(x) transformed to g(x) the x coordinates has increased by +5 any y coordinates has change by -4 i mean when ( 2 , -3) ----> ( 7 , -7) so the answer is (x, y) → (x + 5, y – 4) hope this will help ya !!

6 0

4 years ago

Read 2 more answers

Please help? , no decimals please,please explain to see picture.

dalvyx [7]

Answer:

$8x\sqrt{3xy$