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AnnZ [28]
4 years ago
5

write an equation in slope intercept form perpendicular to 5x+3y= -12 that contains the point (-15,1)

Mathematics
1 answer:
beks73 [17]4 years ago
6 0
Simplify into Y=mX + C form first
y=-5/3 X  - 4
so m = -5/3 for original graph, we convert to perpendicular = 3/5
So new graph = Y= 3/5X + C
to find C we substitute in (-15,1) 
1 = -15(3/5) + C, hence C=10
Y= 3/5 X + 10   <Answer here
-3/5X + Y = 10
-3X + 5Y = 50   <Similar form here (just for viewing)
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