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Yanka [14]
3 years ago
5

Solve the following simultaneouse equation. 3x+y=1 and x²+y²=5​

Mathematics
1 answer:
Serjik [45]3 years ago
3 0

Answer:

x=2/5,      y=11/5

or x=−1y = 2

Step-by-step explanation:

Substitute y=3x+1 in x2+y2=5 to obtain

x2+(3x+1)2=5    ⇒    10x2+6x−4=0

Hence

5x2+3x−2=0    ⇒    5x2+5x−2x−2=0    ⇒5x(x+1)−2(x+1)= 0   ⇒ (5x−2)(x+1)=0

Hence

either

x=2/5, y=3×2/5+1=11/5

or x=−1, y=3×(−1) +1 = −2

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To solve this, follow these steps:

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Please help me with this question
Natali5045456 [20]
Again, In this question too you need to substitute the given variable values into the original expressions. Here, "x" is given as a value of "12" and the variable of "y" is given as as value of "2". A single variable of "x" in the numerator is given in the expression. On the denominator the variable of "y" with a value of "2" is multiplied by a numbered value of "3". So, now showing this by the help of LaTeX.

\mathbf{Since, \: x = 12, \: y = 2}

\mathbf{\therefore \quad \dfrac{12}{3 \times 2}}

\mathbf{\therefore \quad \dfrac{12}{6}}

\mathbf{2}

\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: B) \: 2}}}

Hope it helps.
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Step-by-step explanation:

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