Answer:
Option D. y = 5x + 1
Step-by-step explanation:
From the question given above, the following data were:
Input (x) >>>>>> Output (y)
0 >>>>>>>>>>>> 1
1 >>>>>>>>>>>> 6
2 >>>>>>>>>>>> 11
3 >>>>>>>>>>>> 16
4 >>>>>>>>>>>> 21
To know the the correct answer to the question, we shall apply the equation given in each option to see which will satisfy the table. This can be obtained as follow:
For Option a
y = 3x + 3
x = 0
y = 3(0) + 3
y = 0 + 3
y = 0
y = 3x + 3
x = 1
y = 3(1) + 3
y = 3 + 3
y = 6
For Option b
y = 5x – 4
x = 0
y = 5(0) – 4
y = 0 – 4
y = – 4
y = 5x – 4
x = 1
y = 5(1) – 4
y = 5 – 4
y = 1
For Option c
y = 10x – 9
x = 0
y = 10(0) – 9
y = 0 – 9
y = – 9
y = 10x – 9
x = 1
y = 10(1) – 9
y = 10 – 9
y = 1
For Option d
y = 5x + 1
x = 0
y = 5(0) + 1
y = 0 + 1
y = 1
y = 5x + 1
x = 1
y = 5(1) + 1
y = 5 + 1
y = 6
From the illustrations made above, only option d satisfy the table. Thus, option d gives the correct answer to the question.
You add them and then divide by how many numbers there are.
a. (3+43)/2 = 23
b. 0
c. -1
<u>Answer:</u>
- Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.
<u>Step-by-step explanation:</u>
We know that:
- 48 + 8(b) = Carly's expenditure
- 10(b) = Carly's expenditure
- 48 + 8b = 10b
- B = Boxes of cards
<u>Work:</u>
- 48 + 8b = 10b
- => 48 + 8b - 8b = 10b - 8b
- => 48 = 2b
- => b = 24
<u>Now, let's substitute the value of b into any equation.</u>
<u>Hence, Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.</u>
Hoped this helped.
![BrainiacUser1357](https://tex.z-dn.net/?f=BrainiacUser1357)
Answer:
Question one: Zero slope
Question two: ![m=\frac{0}{4}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B0%7D%7B4%7D)
Step-by-step explanation:
Given the following questions:
<u>Question one:
</u>The following line is what you call a "zero slope." Zero slopes are lines that are neither decreasing or increasing and remain at a constant or just a straight line.
Question two:
Point A = (-2, -3) = (x1, y1)
Point B = (2, -3) = (x2, y2)
Using the formula for slope or rise over run we will solve and find the slope of this line.
![m=\frac{y2-y1}{x2-x1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By2-y1%7D%7Bx2-x1%7D)
![m=\frac{-3--3}{2--2} =\frac{0}{4}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-3--3%7D%7B2--2%7D%20%3D%5Cfrac%7B0%7D%7B4%7D)
![m=\frac{0}{4}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B0%7D%7B4%7D)
The slope of this line is "0/4."
Hope this helps.