Answer:
slope = - 
Step-by-step explanation:
note that BC is perpendicular to AB, hence the slope of BC is the negative reciprocal of the slope of AB
= - 
= -
Can’t see your answer choices but the absolute value of -3 is 3 so I would say 3 is your answer
Answer:
Kenny is 18 years old Andrew is 10 years old Tim is 30 years old and Cameron is 5 years old
Step-by-step explanation:
Let a be Kenny's age , b be Andrew's age , c be Tim's age , d be Cameron's age
( b < a , b<c , d<b)
Kenny is 8 years older than Andrewn = > a = b + 8 (1)
Tim is 3 times as old as Andrew => c = 3 . b (2)
Cameron is 5 years younger than Andrew => d = b-5 (3)
The combined age of the four is 63 => a+b+c+d = 63 (4)
(1),(2),(3),(4) => b+8 + b + 3b + b-5 = 63 <=> 6b + 3 = 63 <=> b = 10
=> a= 10+8 =18, c = 3 . 10 = 30, d= 5
Answer:
The wavelength, of a sound wave with a frequency of 20 waves per second is 15,000,000 m.
Step-by-step explanation:
In this question, we have to calculate the wavelength of a sound wave of frequency 20 waves per second.
We know that the speed of light in air/ vacuum is 
.
Now by the formula v = nλ , where v = speed of light in air/vacuum, n = frequency of the wave and λ = wavelength in meters,
we put the values
= 20 × λ
λ = 
λ = 15,000,000 m
Answer:
The second answer, and possibly the first answer as also true.
She did run a test that would indicate its an unbalanced dice, but this wasn't tried out with a different person throwing the dice.
Step-by-step explanation:
This is because from the computer generator results we see 11 of the 25 values are estimating at 1/5 when we know dice are 1/6 and more than 1/2 show just under 1/5 which balances this to be 1/6
But there are 9/25 tests that showed values under 10 throws found a 6 in 9/25 events = 1/3 approx out of 1/10 of the throws, and 1/3 is still a higher value than 1/6 of the multiple throws so indicates 100 throws would not be enough to tell as we cannot possibly assume her results are comparable with a computer generator.As the computer generator completed 25 x 100 throws and have just compared only x10 in relation to 1/10 of the events of the generated computer. This showing 9 of the 25 (100) throw events in relation scores 1/3 of the results a 6. The answer is she would need to throw somewhere between 1000 and 3000 to compare to the computers results.
