<u>Answer:</u>
Hence, Relation t is a function. The inverse of relation t is a function.
<u>Step-by-step explanation:</u>
We are given the relation as:
x: 0 , 2 , 4 , 6
y: -10 , -1 , 4 , 8
<em>Clearly from the y-values corresponding to the x-values we could see that each x has a single image (single y-value).</em>
Hence, the corresponding relation is a function.
Now we have to find whether the inverse of this relation is a function or not.
When we take the inverse of this function that is the y-values will behave as a pre-image and x-values as its image.
Hence we will see that corresponding to each y-value there is a unique image hence the inverse relation is also a function.
Hence, Relation t is a function. The inverse of relation t is a function.
Answer:
Option D)Neither solution is extraneous.
Step-by-step explanation:
we have
we know that
two possible solutions are x=-7 and x=1
<u><em>Verify each solution</em></u>
Substitute each value of x in the expression above and interpret the results
1) For x=-7
----> is true
therefore
x=-7 is not a an extraneous solution
2) For x=1
----> is true
therefore
x=1 is not a an extraneous solution
therefore
Neither solution is extraneous
Answer:
C
Step-by-step explanation:
y = mx + c
m = (y2 - y1 )/ (x2 - x1)
using (1 , 7) & (2,5)
y2 = 5 y1 = 7 so y2 -y1 = -2
x2 = 2 x1 = 1 so x2 - x1 = 1
m - -2/1 = -2
y = -2x + c
when x =1 y = 7
so 7 = -2 + c
=> c =9
y = -2x + 9
if ordered pairs (2, 5) and (4, 1) used
m = (1-5)/(4-2)
=> m = -4/2
=> m = -2
y = -2x + c
for x =2 y =5
5 = -2*2 + c
=> c = 9
y = -2x + 9
she would have got same equation
I think it’s four. If not then I’m sorry
