Answer:
Third option.
Step-by-step explanation:
You need to cube both sides of the equation. Remember the Power of a power property:
![\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d})\\\\(\sqrt[3]{162x^cy^5})^3=(3x^2y(\sqrt[3]{6y^d}))^3\\\\162x^cy^5=27x^6y^36y^d](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%3D3x%5E2y%28%5Csqrt%5B3%5D%7B6y%5Ed%7D%29%5C%5C%5C%5C%28%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%29%5E3%3D%283x%5E2y%28%5Csqrt%5B3%5D%7B6y%5Ed%7D%29%29%5E3%5C%5C%5C%5C162x%5Ecy%5E5%3D27x%5E6y%5E36y%5Ed)
According to the Product of powers property:
Then. simplifying you get:
Now you need to compare the exponents. You can observe that the exponent of "x" on the right side is 6, then the exponent of "x" on the left side must be 6. Therefore:
You can notice that the exponent of "y" on the left side is 5, then the exponent of "x" on the left side must be 5 too. Therefore "d" is:
Answer:
Step-by-step explanation:
First you need to write it down. Now, 1st step of the math, how many times will 7 go into 4? 0 times. So you have to do how many times 7 goes to 44. It goes in 6 times bc 7 times 7 is 49. Now, subtract 42 form 44 which is 2. Bring down the 2, you get 22. 7 goes into 22 3 times, subtract 21 from 22. One. So your answer is 63 remainder one!
Picking up 8 boxcars after 5 stops makes a total of 40 new boxcars . . . add the original 3 engines, 52 boxcars, and 1 caboose to get a total of . . . 3 + 52 + 1 + 8 + 8 + 8 + 8 + 8 = 96 total cars
15 toys after he starts with 3 toys from a month and then keeps collecting more for 4 month. It would be the over all of 15 toys..Hope that helps<span />
16 t-shirts
because the rate is $6.25
$100/$6.25 =16
Hope this helps ;)
