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3 years ago

? Question

Mathematics

1 answer:

uysha [10]3 years ago

8 0

Answer:

B1: -9, -3, and 10

B2: 5

Step-by-step explanation:

mark brainliest

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What are the values of a 1 and r of the geometric series? 1 3 9 27 81 a 1 = 1 and r = one-third a 1 = one-third and r = 1 a 1 =

Paha777 [63]

Answer:

a₁ = 1

r = 3

Step-by-step explanation:

Since it’s a geometric series then

a₁ = 1 ( because 1 is the first term of the series)

3/1 = 9/3 = 27/9 = 81/27 = 3 then r=3.

Step-by-step explanation:

6 0

2 years ago

Point J is on line segment IK. Given JK = 2x – 1, IK = 3x + 2,

Serhud [2]

Answer:

JK=7

Step-by-step explanation:

From the line segment, since J is on it ,it means the line segment is

represented as I J K

from this illustration, we can say that the longest part of the line segment is from I to K

this means that, IJ +JK =IK

making JK the subject,

JK= IK - IJ

but from the question, JK=2x-1 , IK=3x+2 and IJ=3x-5

substituting them in the expression,

2x-1 =3x+2 -(3x-5)

solving for x

2x-1 =3x+2-3x+5

2x-1 =0+7

2x-1 =7

2x=1+7

2x=8

dividing through by 2

2x/2 =8/2

x=4

but the question says we should find the numerical value for JK

but from the line segment,

JK=2x-1

but now we know the value of x to be 2

so substituting it in the formula

JK= 2(4)-1

JK=8-1

JK=7

therefore, the numerical value for JK is 7

4 0

3 years ago

I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!

frutty [35]

Answer:

17) x=8

18) $x=\sqrt{189}$ or $x= 3\sqrt{21}$

Step-by-step explanation:

So the rule is $a^{2} +b^{2} =c^{2}$ , "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

$x^{2} +x^{2} =(8\sqrt{2}) ^{2}$

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

<em>simplify</em> (╥︣﹏╥)

$2x^2=8^2(\sqrt{2} )^{2}$

$2x^2=64(2)$

$2x^2=128$

$x^{2}= 128/2$

$x^{2} =64$

x=8

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

$c^{2} - b^{2} = a^{2}$

It doesn't matter if you put the one leg value in a or b, just as long as you stick to that same equation you started with the entire time!

$15^{2} -6^{2} =x^{2}$

$225-36=x^{2}$

$x^{2} =189$

$x=\sqrt{189}=3\sqrt{21}$

The more you do these, the easier they'll get, so don't worry!

4 0

3 years ago

Put the following equation of a line into slope-intercept form, simplifying all

Kipish [7]

Answer:

y=1/4x−6

Step-by-step explanation:

Write in slope-intercept form, y = m x + b .

7 0

3 years ago

Read 2 more answers

5a - 24b =-15<br> 10a + 45c =21<br> 48b + 35c = 49

andrew-mc [135]

5a + 15 = 24b so,

10a + 30 = 48b,

sub to third equation,

10a + 30 + 35c = 49

10a + 35c = 19

perform elimination with second equation

10a + 45c = 21

10a + 35c = 19

________________-

10c = 2

c = 1/5

sub to second equation,

10a + (45)(1/5) = 21

10a + 9 = 21

10a = 12

a = 6/5

sub to first equation

(5)(6/5) - 24b = -15

6 + 15 = 24b

21 = 24b

b = 7/8

redo the calculations, correct me if I'm wrong

6 0

3 years ago