Number of ways the second grade students can sit on the first row is 5! = 5P5
Number of ways 15 first grade students can sit in the remaining 20 seats is 20P15
Therefore, required number of ways is 5P5 * 20P15. (option B)
Answer: 14,658,134,400
<u>Step-by-step explanation:</u>
There are 52 numbers to start with. After choosing the first number, there are 51 numbers remaining, etc.
1st and 2nd and 3rd and 4th and 5th and 6th
52 x 51 x 50 x 49 x 48 x 47 = 14,658,134,400
You can also find the answer using the following formula:
Answer:
12/7
Step-by-step explanation:
A reciprocal is similar to inverting or reversing the value in the problem.
Ex: 5/10 would be10/5 or 2/1 when reduced.
The answer would be 5227. If you subtract what is in parenthesis first and then multiply it that should be your answer.
Answer:
x=6
Step-by-step explanation:
Solve for x.
5x-15 = 2x+3
(Move the 2x to the other side of the equation.)
3x-15= 3
(Move the 15 to the right side of the equation.)
3x=18
(Divide both sides by 3 to isolate the variable.)
x=6
I hope this helps!
