A VERTICAL POLE OF CAST A SHADOW OF 4.5m LONG AT THE SAME TIME A TREE OF HEIGHT 24m LONG CAST A SHADOW OF 6m LONG. FIND THE HEIG
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Answer:
28 m
Step-by-step explanation:
The longer side can be found using the Law of Cosines. The semi-diagonals are of length 12 and 20 m, and the angle between them facing the long side is 180° -60° = 120°.
c^2 = a^2 +b^2 -2ab·cos(C)
c^2 = 12^2 +20^2 -2·12·20·cos(120°) = 144 +400 +240 = 784
c = √784 = 28
The longer side is 28 meters.
