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Dmitrij [34]
3 years ago
5

Please answer ASAP and show work so I can answer this test

Mathematics
1 answer:
photoshop1234 [79]3 years ago
6 0

Answer:

ASAP natin to!!!

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The Hayes family and the Rodrigues family use their sprinklers last summer. The water output rate for the Hayes family sprinkler
Elis [28]

Answer:

  • Hayes family: 35 hours
  • Rodrigues family: 40 hours

Step-by-step explanation:

Let x and y represent the usage hours by the Hayes and Rodrigues families, respectively. The problem statement gives us relations that can be used to write equations for volume of use and for total hours.

  15x +30y = 1725 . . . . . total liters of use

  x + y = 75 . . . . . . . . . total hours of use

The second equation lets us write an expression for y:

  y = 75 -x

This can be substituted into the first equation to give ...

  15x +30(75 -x) = 1725

  -15x + 2250 = 1725 . . . . . . simplify

  -15x = -525 . . . . . . . . . . . subtract 2250

  x = 35 . . . . . . . . . . . . . . divide by -15

  y = 75 -35 = 40

The Hayes family used their sprinklers for 35 hours; the Rodrigues family used theirs for 40 hours.

3 0
3 years ago
Over which interval(s) is the function decreasing?
mart [117]

Answer:

<u>B.(-5.5; 0)</u>

Step-by-step explanation:

7 0
3 years ago
Find the coordinates of point Q.
Elis [28]

Answer:

Q(2, 6 )

Step-by-step explanation:

Using the midpoint formula

let the coordinates of Q = (x, y ), then

0.5(x + 10) = 6 ( multiply both sides by 2 )

x + 10 = 12 ( subtract 10 from both sides )

x = 2

and

0.5(y + 6) = 6 ( multiply both sides by 2 )

y + 6 = 12 ( subtract 6 from both sides )

y = 6

Coordinates of Q = (2, 6 )

6 0
3 years ago
How many solutions does the nonlinear system of equations graphed below have?
Sever21 [200]
The answer is d.three
4 0
3 years ago
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 12 cans yields a sample standar
Dennis_Churaev [7]

Answer:

3.30185\leq σ \leq 8.7636

Step-by-step explanation:

the fromula for 100(1-α)% confidence (two sided) for σ is

√(η-1)*s^2/x^2_α/2,V \leq σ \leq √(η-1)*s^2/x^2_(1-α/2,V)               ∴ (v=n+1)

now data given is n = 12 and s=5.2 mg

for 99% CI ,α=0.05  and (n-1)=9 degree of freedom

from chi- square table x^2_(0.025,9)=19.02 ; x_(0.975,9)=2.7

substitute them in above expression we get

3.30185\leq σ \leq 8.7636

7 0
4 years ago
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