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Tom [10]
3 years ago
14

A desk has an are of 42 ft2 if the width is 3.5 feet writ an equation to represent the area

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0

Answer: 42=3.5x              :) .

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1. Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the
Sveta_85 [38]

Answer:

#1) y = -4x + 1; #2) parallel; #3) y = -1/2x + 5/2; #4) y = 2x + 4; #5) Never

Step-by-step explanation:

#1) We want a line that passes through (1, -3) and is parallel to y = 2-4(x-1).  First we simplify our equation using the distributive property:

y = 2-4(x-1) = 2-4(x) -4(-1) = 2-4x--4 = 2-4x + 4 = -4x + 6

Lines that are parallel have the same slope; this means we want a line through (1, -3) with a slope of -4.  Using point-slope form,

y-y_1=m(x-x_1)\\\\y--3=-4(x-1)\\\\y+3=-4(x)-4(-1)\\\\y+3=-4x+4\\\\y+3-3=-4x+4-3\\\\y=-4x+1

#2) We must first write our second equation in slope-intercept form by isolating the y term:

2x+y=7

Subtract 2x from each side"

2x+y-2x = 7-2x

y = -2x+7

This means the slope is -2; the slopes are the same, so the lines are parallel.

#3) The slope of our given equation is 2.  To be perpendicular, the second line must have a slope that is a negative reciprocal (flipped and opposite signs); this makes it -1/2.  Using point-slope form,

y-0=\frac{-1}{2}(x-5)\\\\y=\frac{-1}{2}(x)+\frac{-1}{2}(-5)\\\\y=\frac{-1}{2}x+\frac{5}{2}

#4) The slope of Main Street on the diagram, found by using rise/run, is 2.  This means the bike path will also have a slope of 2 in order to be parallel.  The park entrance is at (0, 4).  This makes the equation y = 2x+4.

#5) Two lines with the same slope are always parallel.  They are never perpendicular.

3 0
3 years ago
Read 2 more answers
(a) Find the three-digit number that increases by 30% when each of its
Elden [556K]

Step-by-step explanation:

So a three digit number can be expressed as: 100a + 10b + c where a is the third digit, b is the second digit, and c is the first digit. Or in other words a is the hundreds place, b is the tens place, and c is the ones place. When something "increases" by 30%, it is 130% it's original value, and to calculate how much that is, you simply convert 130% to a decimal by dividing by 100, which gives you 1.30. And since all the digits are increased by 1, you have the equation:

100(a+1) + 10(b+1) + 1(c+1) = 1.30(100a+10b+c)

Distribute the multiplication on the left side:

100a+100+10b+10+c+1=1.30(100a+10b+c)

Distribute the multiplication on the right side:

100a+100+10b+10+c+1=130a+13b+1.3c

Add like terms on the left side:

100a+10b+c+111=130a+13b+1.3c

Subtract 100a, 10b, and c from both sides

111=30a+3b+0.3c

So "technically" you can just plug in any two values, and then solve for the last value, but since you have a 3 digit number, you have the restriction of a < 10, b < 10, and c < 10, and also a, b, and c, should only be integers and all have the same sign or it wouldn't be a 3 digit number.

So let's start with a, since it has the highest coefficient, well you can fit 30 into 111, 3 times without going over so that's the first value

111 = 30(3) + 3b + 0.3c

111 = 90 + 3b + 0.3c

Now subtract the 90 from both sides

21=3b+0.3c

Well 3 can fit into 21, 7 times!

21 = 3(7) + 0.3c

21 = 21 + 0.3c

subtract 21 from both sides

0 = 0.3c

and now obviously c is 0, if you want you can divide both sides by 0.3 but it's a bit redundant

c = 0

This gives you the three values, a=3, b=7, c=0. which is the number 370. Now let's double check. Adding 1 to each digit would give you 481 and 481/370 = 1.3, so it is correct!

part b:

So to prove there is no three digit number, is to realize there is no solution, given the restriction or integers, greater than or equal to 0, and less than 10, and all of them must have the same sign.

So let's start with the same equation except this time instead of 1.3 it's 1.4

100(a+1) + 10(b+1) + 1(c+1) = 1.40(100a+10b+c)

Distribute on the left side;

100a+100+10b+10+c+1=1.40(100a+10b+c)

Distribute on the right side:

100a+100+10b+10+c+1=140a + 14b + 1.4c

Add like terms on left side:

100a + 10b + c + 111 = 140a + 14b + 1.4c

Subtract 100a, 10b, and c from both sides:

111 = 40a + 4b + 0.4c

Now to do the same process, let's start by finding how many times we can fit 40 into 111, and if you're wondering why we start with 40, it's because let's say for example I just say, I can fit another 40 into it, but I decide not to, and let b do that, well even if it's just 40, b will have be at least 10, which does not fit our restrictions, so you have to fit as many 40's into the number first then go the other numbers.

So only 2 40's can fit in 111 without going over the value

111 = 40(2) + 4b + 0.4c

Subtract 80 from both sides

31=4b+0.4c

4 can fit into 31, 7 times

31 = 4(7) + 0.4c

31 = 28 + 0.4c

subtract 28 from both sides

3 = 0.4c

divide both sides by 0.4

7.5 = c.

Since c is not an integer there is no 3 digit number that exists that increases by 40% whenever you increase it by 1.

7 0
2 years ago
What is the value of x in the equation 3x - 4 (2x - 5) = 15
Zepler [3.9K]

Hey there! I'm happy to help!

Here is our equation

3x - 4 (2x - 5) = 15

First, we will sue the distributive property to remove the parentheses. The term outside the parentheses is -4, so that is what we multiply the insides by.

3x-8x+20=15

We combine our like terms (our x-values).

-5x+20=15

We subtract 20 from both sides.

-5x=-5

We divide both sides by -5.

x=1

Have a wonderful day and keep on learning! :D

3 0
3 years ago
Read 2 more answers
Which of the following statements is not true?
Amiraneli [1.4K]

The above question is asking us to check if the exponents are written in the correct way or not.Let us look at the options one by one.

1) The exponent denotes the number of time the letter or number is multiplied.We have six x which are multiplied so the exponent for x which is 6 is right .The exponent is written correct .

2)We have seven A which are multiplied and five B multiplied making the exponent of A as 7 and B as 5 .The exponents are written correct.

3)There are six b and six c .The exponent rule has been followed here that is we can keep bc inside parenthesis and make 6 as the exponent.

4)Here exponent for x,y,z all are 5. we can not remove the exponent of x and y .It is not following the exponent rule .

Option 4 is not true.

4 0
3 years ago
Read 2 more answers
I need help dec iding if the triangle below are congruent in
lozanna [386]

Answer:

They're congruent if they have the exact same sides and the exact same angles. So from what i can see, yes they are congruent.

Step-by-step explanation:

7 0
3 years ago
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