All categories

3 years ago

Can someone help me out with this at all?

Mathematics

1 answer:

dsp733 years ago

6 0

Answer:

1 maps to 1

2 maps to 3

3 maps to 2

Step-by-step explanation:

the correctly assigned answer options describe everything.

there is not much else to say and explain.

these are all true statements due to the symmetry principle of a circle.

when 2 direct connections of two points on the circumference of a circle have the same length, then also their bent distances on the circumference of the circle are the same. and vice versa.

and yes, the perpendicular radius (or diameter) of the circle towards such a line cuts this line in half.

You might be interested in

) Write an expression that is equivalent to 3(7 + x).

Mamont248 [21]

same question how many times...?

4 0

3 years ago

Read 2 more answers

About your photograph 4 in wide and 6in long the photograph is enlarged and their larger is proportional to the original photogr

Bad White [126]

18 inches.

12/4=3 so you would multiply 6•3 to get 18

4 0

3 years ago

Read 2 more answers

Can y’all please help me answer these questions

mario62 [17]

Step-by-step explanation:

⇒ $V = \pi r^{2}h$

⇒ $V = \pi(10)^{2}(40)$

⇒ $V = 4000\pi$

⇒ $V = 12566.4cm^{3}$

⇒ $V = \frac{1}{3}\pi r^{2}h$

⇒ $V = \frac{1}{3}\pi (8)^{2}(h)$

As we know the radius and slant height, we can use Pythagoras' Theorem to find the perpendicular height.

⇒ $a^{2} + b^{2} = c^{2}$

⇒ $(8)^{2} + h^{2} = 20^{2}$

⇒ $h = \sqrt{20^{2} - 8^{2}}$

⇒ $h = 4\sqrt{21}$

Now substitute this into the volume formula.

⇒ $V = \frac{1}{3}\pi (8)^{2}(4\sqrt{21})$

⇒ $V = \frac{256\sqrt{21} }{3}\pi$

⇒ $V = 1228.5mm^{3}$

⇒ $V = l^{3}$

⇒ $V = (3.1)^{3}$

⇒ $V = 29.8inches^{3}$

⇒ $V = \frac{1}{3}lwh$

⇒ $V = \frac{1}{3}(12)(4)(6)$

⇒ $V = 96inches^{3}$

6 0

3 years ago

Read 2 more answers

I need help on this asap, I'm giving 39 POINTS and mark BRAINLIEST the question is on the pic! thankss

shtirl [24]

Answer: I’m pretty sure it’s c also

3 0

3 years ago

If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds a

Luba_88 [7]

Answer:

$12C5 *(12C3) = 792*220 =174240 ways$

Step-by-step explanation:

For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52

First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

$nCx = \frac{n!}{x! (n-x)!}$

So then 12 C5 would be equal to:

$12C5 = \frac{12!}{5! (12-5)!}=\frac{12!}{5! 7!} = \frac{12*11*10*9*8*7!}{5! 7!}= \frac{12*11*10*9*8}{5*4*3*2*1}=792$

So we have 792 was in order to select 5 diamonds from the total of 12

Now in order to select 3 clubs from the total of 12 we have the following number of ways:

$12C3 = \frac{12!}{3! 9!}=\frac{12*11*10*9!}{3! 9!} =\frac{12*11*10}{3*2*1}=220$

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:

$(12C5)*(12C3) = 792*220 =174240 ways$

3 0

3 years ago