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3 years ago

Write an equation that represents the line.

Mathematics

1 answer:

Vladimir79 [104]3 years ago

7 0

Answer:

$y = \frac{7}{5}x + 6.8$

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Question Help When purchasing bulk orders of batteries, a toy manufacturer uses this acceptance sampling plan: Randomly select

horrorfan [7]

Answer:

The probability is $P(X \le 2 ) = 0.9072$

The company will accept 90.72% of the shipment and will reject $(100 -90.72) = 9.2\%$ of the shipment , so many of the shipment are rejected

Step-by-step explanation:

From the question we are told that

The sample size is n = 36

The proportion that did not meet the requirement is $p = 0.03$

Generally the probability that the whole shipment is accepted is equivalent to the probability that there is at most 2 batteries that do not meet the requirement , this is mathematically represented as

$P(X \le 2 ) = [ P(X = 0 ) + P(X = 1 ) + P(X = 0)]$

=> $P(X \le 2 ) = [ [^{n}C_0 * (p)^{0} *(1-p)^{n-0} ] + [^{n}C_1 * (p)^{1} *(1-p)^{n-1} ] + [^{n}C_2 * (p)^{2} *(1-p)^{n-2} ]]$

Here C stands for Combination (so we will be making the combination function in our calculators )

=> $P(X \le 2 ) = [ [^{36}C_0 * (0.03)^{0} *(1-0.03)^{36-0} ] + [^{36}C_1 * (0.03)^{1} *(1-0.03)^{36-1} ] + [^{36}C_2 * (0.03)^{2} *(1-0.03)^{36-2} ]]$

=> $P(X \le 2 ) = [ [1 * 1 * 0.3340 ] + [36* 0.03 *0.3444 ] + [630 * 0.0009 *(0.355 ]]$

=> $P(X \le 2 ) = 0.9072$

The company will accept 90.72% of the shipment and will reject $(100 -90.72) = 9.2\%$ of the shipment , so many of the shipment are rejected

8 0

3 years ago

Simplify 35x-35<br> over 14x-49

artcher [175]

Answer: Distributive property a(b+c) = ab + ac

-5(7)x + 7(7) = -35x + 49 (D)

7 0

2 years ago

The area of a circle is 30.8m2.<br> Find the length of the diameter rounded to 1 DP.

andre [41]

Area of a circle = pi • r^2

We need to isolate for r.

A/pi = r^2

r = sqrt(A/pi)

r = sqrt(30.8/pi)

r = 3.1311251164

Diameter = 2r

Diameter = 6.26225023

Diameter = 6.3 m

8 0

2 years ago

Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).

Dvinal [7]

<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:

..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>

4 0

3 years ago

What's the negative reciprocal of 5? Question 12 options: A) 1∕5 B) –5 C) –1∕5 D) 5

levacccp [35]

Answer:

$\huge\boxed{C)\ -\dfrac{1}{5}}$

Step-by-step explanation:

The reciprocal of 5: $\dfrac{1}{5}$

The negative reciprocal of 5: $-\dfrac{1}{5}$

7 0

2 years ago