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dem82 [27]
3 years ago
6

Identify the index in the radical below. A. 1 B. 2 C. 3 D. 4

Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

It is four/4 I believe D.4

Step-by-step explanation:

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You have to evaluate<br> 3³+11-10÷2×4=w
denis23 [38]

Answer:

18

<u><em>Brainliest, please!</em></u>

Step-by-step explanation:

3^3 + 11 - 10 / 2 x 4 = w

27 + 11 - 10 / 2 x 4 = w

27 + 11 - 5 x 4 = w

27 + 11 - 20 = w

38 - 20 = w

w = 18

3 0
3 years ago
Hey yall like dat sweet algeba? then 5ab - 2c where a = 2 b = 3 and c is 0. gud luck daddio
nordsb [41]

Answer:

30

Step-by-step explanation:

5ab-2c

5(2)(3)-2(0)

5(6)-2(0)

30-0

30

7 0
3 years ago
How to factor out xsquared+6x-27
Aleks04 [339]
X^2 + 6x - 27
(x - 3)(x + 9)

The answer is: (x - 3)(x + 9).
5 0
3 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = (8, 4), v = (9, -9)
Usimov [2.4K]

Answer:

<em>71.6 degrees </em>

Step-by-step explanation:

The formula for calculating the angle between two vectors is expressed as;

u.v = |u||v|cos theta

u.v = (8, 4).(9, -9)

u.v = 8(9)+4(-9)

u.v = 72-36

u.v = 36

|u| = √8²+4²

|u| = √64+16

|u| = √80

|v| = √9²+(-9)²

|v| = √81+81

|v| = √162

36 = √80*√162 cos theta

36 = √12960 cos theta

36 = 113.84 cos theta

cos theta = 36/113.84

cos theta = 36/113.84

cos theta = 0.3162

theta = arccos (0.3162)

<em>theta = 71.6 degrees </em>

<em>Hence the angle between the given vectors is 71.6 degrees </em>

7 0
3 years ago
Read 2 more answers
This figure is made up of a triangle and a semicircle. What is the area of the figure? Use 3.14 for π . Enter your answer, as a
lana66690 [7]
Area of ∆ = 1/2 times its base × height
=1/2 × 4 × 5 UNIT²
=10 unit²
Area of semicircle = πr²/2
= (3.14)(4)²/2
=25.12 unit²

Therefore area of figure= 10+25.12 unit² = 35.12 unit²

Hope it helps!
6 0
3 years ago
Read 2 more answers
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