follow the lines in the order of the letters. look at each corner showering that the angle = 90°. the last option is the only one that proves that it is a right angle.

hope this helps

6 0

3 years ago

EASY BRAINLIEST PLEASE HELP!!

butalik [34]

Answer:

see below

Step-by-step explanation:

<h3>Proposition:</h3>

Let the diagonals AC and BD of the Parallelogram ABCD intercept at E. It is required to prove AE=CE and DE=BE

<h3>Proof:</h3>

1)The lines AD and BC are parallel and AC their transversal therefore,

$\displaystyle \angle DAC = \angle ACB \\ \ \qquad [\text{ alternate angles theorem}]$

2)The lines AB and DC are parallel and BD their transversal therefore,

$\displaystyle \angle BD C= \angle ABD \\ \ \qquad [\text{ alternate angles theorem}]$

3)now in triangle ∆AEB and ∆CED

$\displaystyle \angle EAD=\angle ECB$
$\angle EDA=\angle EBC$
$\displaystyle AD=BC$

therefore,

$\displaystyle \Delta AEB \cong \Delta CED$

hence,

AE=CE
DE=BE

Proven

6 0

3 years ago