Answer:
Slope: 2
y = 2x + 50
Step-by-Step Solution:
Slope: rise/run = 40/20 = 4/2 = 2
y = mx + b
m= slope = 2
b= y-intercept = 50
y = 2x + 50
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Answer:
The amount of Polonium-210 left in his body after 72 days is 6.937 μg.
Step-by-step explanation:
The decay rate of Polonium-210 is the following:
(1)
Where:
N(t) is the quantity of Po-210 at time t =?
N₀ is the initial quantity of Po-210 = 10 μg
λ is the decay constant
t is the time = 72 d
The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.
First, we need to find the decay constant:
(2)
Where t(1/2) is the half-life of Po-210 = 138.376 days
By entering equation (2) into (1) we have:
Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.
I hope it helps you!
2 1/2 because 50-20 leaves you with 30 so you have one. Than 30-20 leaves you with 10. Now you have two. There isn't another 20 but 10 is half of twenty so that gives you a half so it is 2 1/2