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Liula [17]
3 years ago
5

A loaf of bannana bread serves 6 guests. There will be 47 guests attending the faculty breakfast. Which expression shows how man

y loaves are needed to serve them all A. 47 divided by 6 is 7 R 5, so 7 loaves are needed.
B. 47 divided by 6 is 7 R 5, so 8 loaves are needed.
C. 47 plus 6 is 53, so 53 loaves are needed.
D. 47 minus 6 is 41, so 41 loaves are needed




Please answer
Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0
Many factors should be included
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Answer:

{3xl42}

Step-by-step explanation:

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I have to right a statistic question would this be one Out of 60 7th graders 45 or 75% of them prefer to play sports after schoo
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Answer:

This really isn't a question. I can help you out with writing one.

John randomly selected 45% of seventh grade students in his school and asked them what their favorite time to play sports was. Of the students surveyed, 51 prefer to play sports after school. Based on this data, what is the most reasonable prediction of seventh graders in his entire grade?

Step-by-step explanation:

To answer my question, you would set up a proportion.

  \frac{9}{20} = \frac{51}{x}  <-- the answer to that question will will be 113.

5 0
3 years ago
True or false: if a figure is a hexagon, then it is a regular polygon
Elan Coil [88]
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4 0
3 years ago
Mike saves $42 a week for 7 weeks. During his 8-day vacation, he plans to spend $8.25 each day for snacks. Which expression show
Alla [95]
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5 0
3 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
3 years ago
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