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3 years ago

Help me please I'm not sure

Mathematics

2 answers:

Ahat [919]3 years ago

8 0

Help you with what? Be specific.

Galina-37 [17]3 years ago

6 0

Those are all just simple addition and subtraction problems.. just use a calculator if you're having trouble

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Please help, This is confusing. I'll mark brainiest

Sliva [168]

Answer: a.

Look at the tables closely, many of them are either trick questions or flat out wrong.

7 0

3 years ago

Given the functions f(x) = 3(0.56)^x and g(x) = 6(4)^x

rodikova [14]

A) f(x) is decreasing because the base is less than 1.
0.56 is close to 0.5, so its like saying that you are taking half each time, therefore the value is getting smaller.

g(x) is increasing because the base is greater than 1.
you are multiplying by 4 each time, making the value bigger.

B ) The y-intercept is where x=0.
Anything to the '0' power is 1. Therefore the y-intercept is equal to the coefficient in front of each function.
f(x) = 3 , g(x) = 6

C) Just plug in x=4 to each function in a calculator.
f(4) = 0.295
g(4) = 1536

7 0

4 years ago

Determine if the function f(x)=44−x2‾‾‾‾‾‾√ satisfies the Mean Value Theorem on [0, 2]. If so, find all numbers c on the interva

lina2011 [118]

Answer:

The function f(x) satisfies the Mean Value Theorem

Step-by-step explanation:

Mean Value Theorem states that if f be a function such that,

It is continuous on [a, b].

It is differentiable on (a, b).

Then there is at least a number c in (a, b) such that,

$f'(c) = \frac{f(b) - f(a)}{b-a}$

Here, the given function,

$f(x) = \sqrt{44-x^2}$

∵ f(x) is defined for all real values x for which 44-x² ≥ 0

44 ≥ x² ⇒ ±√44 ≥ x ⇒-√44 ≤ x ≤ √44

Thus, f(x) is continuous on [0, 2],

$f'(x) = \frac{1}{2\sqrt{44-x^2}}(-2x) =-\frac{x}{\sqrt{44-x^2}}$

∵ f'(x) is defined for all values on the interval (0, 2),

Thus, f(x) is differentiable on (0, 2),

Now,

$f'(c) = -\frac{c}{\sqrt{44-c^2}}$

$\frac{f(2) - f(0)}{2-0}=\frac{\sqrt{44-4}-\sqrt{44}}{2}=\frac{\sqrt{40}-\sqrt{44}}{2}=\sqrt{10}-\sqrt{11}$

$-\frac{c}{\sqrt{44-c^2}}=\sqrt{10}-\sqrt{11}$

$\frac{c^2}{44-c^2}=10 + 11 - 2\sqrt{110}$

$c^2 = (44-c^2)(21-2\sqrt{110})$

$c^2 = 924 - 88\sqrt{110} - c^2(21 - 2\sqrt{110})$

$c^2 + (21 - 2\sqrt{110})c^2 = 924 - 88\sqrt{110}$

$(22 - 2\sqrt{110})c^2 = 924 - 88\sqrt{110}$

$c^2 = \frac{924 - 88\sqrt{110}}{22 - 2\sqrt{110}}$

$c=\sqrt{ \frac{924 - 88\sqrt{110}}{22 - 2\sqrt{110}}}\approx 1.012\in (0, 2)$

Hence, the function f(x) satisfies the Mean Value Theorem

7 0

4 years ago

A sphere with a radius of 3 cm has the same volume as a cone with a radius of 6 cm. What is the height of the cone?

Amiraneli [1.4K]

Try this option:

$if \ the \ volume \ of \ the \ sphere \ is \ the \ same \ one \ as \ a \ cone, \ then \ V_s=V_c; \ \ \frac{4 \pi}{3}*3^3=\frac{1}{3} \pi*6^2*h_c; \ => \ h_c=3(cm)$

answer: B

5 0

3 years ago

Read 2 more answers

2. The formula below, the legs of the triangle are a and b. The hypotenuse is c.

jonny [76]

Answer:

Maybe True

Step-by-step explanation:

Hence, to find the area of a triangle, we need to know the base (b) and height (h) of it. This formula is applicable to all types of triangles, whether it is scalene, isosceles or equilateral.

<h2>BRAINILIEST PLEASE </h2>

8 0

3 years ago

Read 2 more answers