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lesya [120]
3 years ago
12

If the ratio of the radii of two spheres is 2:3, the ratio of their surface areas will be 8:27.

Mathematics
1 answer:
Slav-nsk [51]3 years ago
4 0
<span>The ratio of 2 similar areas is the square of the ratio of their RADIUS or (sides)
R²=(2/3)² = 4/9 This should be the answer

Whereas R³ = (2/3)³ = 8/27 is the ratio of their volume & not area



</span>
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A car advertisement claims that a certain car can accelerate from rest to 70 km/hr in 7 seconds find the car acceleration
iVinArrow [24]

Answer:

acceleration \approx 2.78\,\,\frac{m}{s^2}

Step-by-step explanation:

The acceleration is the change in velocity per unit of time.

Therefore to have this rate in appropriate units that can combine, we re-write the change from 0 to 70 km/h in meters per second using:

70 \frac{km}{h} = \frac{70000}{3600} \frac{m}{s}

so in this case the acceleration becomes:

accel=\frac{change\,\,vel}{change\,\,time} =\frac{70000m}{3600\,*7\,s^2} \approx 2.78\,\,\frac{m}{s^2}

7 0
3 years ago
4 people are going to a dinner party. Each person at
vladimir2022 [97]

Answer:

92 pounds

Step-by-step explanation:

Here is the complete question ;

4 people are going to a dinner party. Each person at the party will eat 23 pound of cake. If you can only buy whole pounds of cake, how many pounds should you buy?

total pounds to be bought = number of people at the party x total pounds they would eat

4 x 23 = 92 pounds

7 0
3 years ago
Express the given integral as the limit of a riemann sum but do not evaluate: the integral from 0 to 3 of the quantity x cubed m
WARRIOR [948]
We will use the right Riemann sum. We can break this integral in two parts.
\int_{0}^{3} (x^3-6x) dx=\int_{0}^{3} x^3 dx-6\int_{0}^{3} x dx
We take the interval and we divide it n times:
\Delta x=\frac{b-a}{n}=\frac{3}{n}
The area of the i-th rectangle in the right Riemann sum is:
A_i=\Delta xf(a+i\Delta x)=\Delta x f(i\Delta x)
For the first part of our integral we have:
A_i=\Delta x(i\Delta x)^3=(\Delta x)^4 i^3
For the second part we have:
A_i=-6\Delta x(i\Delta x)=-6(\Delta x)^2i
We can now put it all together:
\sum_{i=1}^{i=n} [(\Delta x)^4 i^3-6(\Delta x)^2i]\\\sum_{i=1}^{i=n}[ (\frac{3}{n})^4 i^3-6(\frac{3}{n})^2i]\\&#10;\sum_{i=1}^{i=n}(\frac{3}{n})^2i[(\frac{3}{n})^2 i^2-6]
We can also write n-th partial sum:
S_n=(\frac{3}{n})^4\cdot \frac{(n^2+n)^2}{4} -6(\frac{3}{n})^2\cdot \frac{n^2+n}{2}

4 0
3 years ago
Whats 5 plus 73 pls help someone
trasher [3.6K]
78 is your answer............
8 0
3 years ago
Read 2 more answers
Hurry which one <br> A. 435<br> B. 512<br> C. 870<br> D. 1024
evablogger [386]

Answer:

Step-by-step explanation:

surface area of cuboid=2(l*b+b*h+h*l)

=2(15*15+15*7+7*15)

=2(225+105+105)

=2*435

=870

8 0
3 years ago
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