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3 years ago

Récord the product. 59×38

Mathematics

2 answers:

MrRissso [65]3 years ago

8 0

The product of 59 x 38=2,242
answer=2,242

tatuchka [14]3 years ago

3 0

59*38=2,242
steps broken down are:
8*9=72
8*50=400
30*9270
30*50=1,500
then add them all together for your answer.

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Which rules would result in a triangle A being congruent to or not congruent to B?

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The bottom one and third one are not congruent while everything else is.

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3 years ago

Square root of 15-x=-3+Square root of 2x+3 Solve for x

PSYCHO15rus [73]

$
\sqrt{15-x}=-3\sqrt{2x+3}\impliedby \textit{divide by -3}
\\ \quad \\
\cfrac{\sqrt{15-x}}{-3}=\sqrt{2x+3}\impliedby \textit{squares both sides}
\\ \quad \\
\left( \cfrac{\sqrt{15-x}}{-3} \right)^2=(\sqrt{2x+3})^2\implies 
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\\ \quad \\
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5 0

3 years ago

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Savatey [412]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

3x^2+5x-28=0 solve this for me please

jok3333 [9.3K]

Answer:

x= 7/3

x=-4

Step-by-step explanation:

Use the quadratic formula

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2.3

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3 years ago

Three numbers are in the ratio 3:9:10. If 10 is added to the last number, then the three numbers form an arithmetic progression.

MrRa [10]

Answer:

 The numbers are 6, 18, and 30 

Step-by-step explanation:

If the three numbers are in the ratio of 3:9:10,

let the numbers be 3x, 9x and 10x.

If 10 is added to the last number to form an arithmetic progression

Then, 3x 9x (10x+10) are the progression

The common difference of an arithmetic progression (d) = T₂ - T₁ = T₃ - T₂

T₂-T₁ = T₃ - T₂ .............. Equation 1

Where T₁ = first term of the progression, T₂ = Second term of the progression, T₃ = third term of the progression

Given: T₁ = 3x, T₂ = 9x, T₃ = 10x +10

Substituting these values into equation 1

9x-3x = (10x+10)-9x

Solving the equation above,

3x = 10+x

3x-x = 10

2x = 10

x = 10/2

x = 2.

Therefore the numbers are 6, 18, and 30 

7 0

3 years ago