Answer:
Step-by-step explanation:
2/cos^2(theta) - sin^2(theta)/cos^(theta) = p
(2 - sin^2(theta) ) / cos^2(theta) = p
cos^2(theta) = 1 - sin^2(theta) Relationship between sines and cosines
2 - sin^2(theta)/ (1 - sin^2(theta) ) = p Everything is now in terms of sines
sin^2 (theta) = 1 / csc ^2 (theta) sin^(theta) = 1/csc(theta)
2 - 1/csc^2(theta) Make Left over csc(theta)
============== = p
1 - 1/csc^2(theta)
2 csc^2(theta) - 1
------------------------
csc^2(theta)
================ = p Cancel out denominators (csc^2(theta))
csc(theta) - 1
-------------------
csc^2(theta)
2 csc^2 (theta) - 1
=============== = p Multiply both sides by csc^2(theta) - 1
csc^2(theta) - 1
2csc^2(theta) - 1 = p*csc^2(theta) - p Collect csc^2(theta) on the left, p on the right.
csc^2(theta) (2 - p) = 1 - p
csc^2(theta) = (1 - p)/(2 - p)
-12, -8, -1, 0, 3
least to greatest :D
The correlation coefficient is .574822477
Answer:
(a)4.17 metres
(b)6.9999 seconds
(c)f⁻¹, t= 2ᶠ⁽ᵗ⁾
Step-by-step explanation:
f(t)=log₂t
(a) If t=18 seconds
f(18)=log₂18= log ₂(2X9)
=log ₂2 + log ₂9
=1+(log9/log2)
=1 + 3.1699 =4.17 metres
f(18)=4.17 metres.
(b)If f(t)=2.80735, we want to determine the value of t.
f(t)=log₂t
2.80735=log₂t
Changing from logarithm form to index form
t= 2^(2.80735)
=6.9999 seconds
(c)f(t)=log₂t
Next, We want to determine f⁻¹
If y=log₂t
Changing to exponential form
t=2ʸ
f⁻¹, t= 2ᶠ⁽ᵗ⁾.