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bulgar [2K]
3 years ago
9

Immediately after filling my gas tank, I drove 237.1 miles to my favorite campground. I filled my tank again at the campground,

and computed that I got 28.7 miles per gallon on the trip. How many gallons of gas did I use on the trip to the campground
Mathematics
1 answer:
Kazeer [188]3 years ago
3 0

Answer:

57,838.4 - 57,491.9 = 346.5 miles

346.5/17.5 = 19.8 miles per gallon.

Hope this helps :-)

Step-by-step explanation:

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mars1129 [50]

Answer:

0

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8 0
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Divide<br>a) (4a-4b)÷(a-b)​
SashulF [63]

Answer:

4a+4b

Step-by-step explanation:

8 0
3 years ago
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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So \mu = 373, \sigma = 67

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So n = 5, s = \frac{67}{\sqrt{5}} = 29.96

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 373}{29.96}

Z = 1.23

Z = 1.23 has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So \mu = 526, \sigma = 107

B) What is the probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes?

So n = 5, s = \frac{107}{\sqrt{5}} = 47.86

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 526}{47.86}

Z = -2.42

Z = -2.42 has a pvalue of 0.0078.

So there is a 1-0.0078 = 0.9922 = 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

7 0
3 years ago
Match each whole number with a rational, exponential expression. 1. 512 2. 8 3. 343 4. 216 5. 729 6.
Crazy boy [7]

Answer:

1. 2^9 = 512

2. 2^3 = 8

3. 7^3 = 343

4. 6^3 = 216

5. 3^6 = 729

Step-by-step explanation:

To start we have to express the number as a multiplication of prime numbers, from there we can take the expression as a power

1.

2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 512

2^9 = 512

2.

2 x 2 x 2 = 8

2^3 = 8

3.

7 x 7 x 7 = 343

7^3 = 343

4.

6 x 6 x 6 = 216

6^3 = 216

5.

3 x 3 x 3 x 3 x 3 x 3 = 729

3^6 = 729

6 0
3 years ago
In a classroom of 28 students: 19 of the students have brown eyes 13 of the students wear glasses 7 of the students do not have
V125BC [204]

Total students = 28

Students with brown eyes = 19

students wear glasses = 13

Not brown eyes or no glasses = 7


Not brown eyes = 28 - 19 = 9

Not wearing glasses = 28 - 13 = 15

Not brown eyes and wearing glasses = 15 - 9 = 6

Brown eyes and wearing glasses = 13 - 6 = 7 <==== answer

7 0
3 years ago
Read 2 more answers
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