Answer:
Step-by-step explanation:
h(t) = -16t² + 14400
0= -16t² + 14400
(1/-16)×-14400=-16t²(1/-16)
900=t²

30=t
4a+3b-(-2a-3b)
=4a+3b+2a+3b
=6a+6b
=6(a+b)
(2,2) and (-2,-2)
(2,2) would be in the first quadrant, while (-2,-2) would be in the third quadrant.
If
, then

Solve for <em>x</em> :

(Yes, bases can be negative.)