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skelet666 [1.2K]
3 years ago
7

Please help me ASAP Thanks

Mathematics
2 answers:
Art [367]3 years ago
4 0

A. 11+n

B. 6n

C. n÷10

D. n-7

E. 7-n

F. n+15

G. n-8

H. 3/4n

I. n÷0.20

J. 24/n

Mariana [72]3 years ago
4 0
The correct answer is B
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Select the two values of x that are roots of this equation.<br> 2x+11x+15= 0
Amiraneli [1.4K]

Answer:

The roots of the equation are x=-3 and x=-2.5

Step-by-step explanation:

<u><em>The correct quadratic equation is</em></u>

2x^2+11x+15=0

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^{2} +11x+15=0  

so

a=2\\b=11\\c=15

substitute in the formula

x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}

x=\frac{-11(+/-)\sqrt{121-120}} {4}

x=\frac{-11(+/-)\sqrt{1}} {4}

x=\frac{-11(+/-)1} {4}

x_1=\frac{-11(+)1}{4}=-2.5

x_2=\frac{-11(-)1}{4}=-3

therefore

The roots of the equation are x=-3 and x=-2.5

5 0
3 years ago
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MA_775_DIABLO [31]
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2 years ago
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