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andrey2020 [161]
3 years ago
11

The formula for calculating wage is

Mathematics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

Dnbsflvi jvidkdkeicucyccgdmjcjvh

Step-by-step explanation:

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What is the equation ?
andreev551 [17]

Answer:

y=x-5

Step-by-step explanation:

y-2=(7-2)/(12-7)(x-7)

y=1(x-7)+2

y=x-5

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2 years ago
Someone please help me I don’t understand this
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Answer:

huh

Step-by-step explanation:

8 0
2 years ago
Marissa bought x shirts that cost $19.99 each and y pairs of shorts that cost $14.99 each. The next day she went back to the sto
zlopas [31]

Answer:

<h2>19.99(x+3)+ 14.99(y+4)</h2>

Step-by-step explanation:

Step one:

given data

day one

x shirts that cost $19.99 each and

y pairs of shorts that cost $14.99 each.

Day two

3 more shirts that cost $19.99 each and

4 more pairs of shorts cost $14.99 each.

Step two:

the total number of shirts is

x+3

and the total number of shorts is

y+4

The total cost is ex[ressed as

19.99(x+3)+ 14.99(y+4)

7 0
2 years ago
Read 2 more answers
The daily average temperature in Santiago, Chile, varies over time in a periodic way that can be modeled approximately by a trig
natali 33 [55]

Answer:

a) the trigonometric function is;

y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5

b) y = 28.36^0 \ C    ( to two decimal places)

Step-by-step explanation:

This data can be represented by the sinusoidal function of the form :

\mathbf{y = A sin (Bt -C)+D}

where A = amplitude and which can be determined via the formula:

A = \dfrac{largest \ temperature -  lowest \ temperature}{2}

A = \dfrac{29-14}{2}

A = \dfrac{15}{2}

A = 7.5° C

where B = the frequency;

Since the data covers a period of 3 days ; then \dfrac{2 \pi}{B } =365

B = \dfrac{2 \pi}{365}   ( where 365 is the time period )

The vertical shift is found by the equation D;

D =  \frac{largest \ temperature + lowest \ temperature}{2}

D = \frac{29+14}{2}

D = 21.5

Replacing the values of A ; B and D into the above sinusoidal function; we have :

y = 7.5 sin (\frac{2 \pi}{365}t -C) + 21.5

From the question; when it is 7th of the year ( i.e January 7);

t =  7 and the temperature (y) = 29° C

replacing that too into the above equation; we have:

29= 7.5 sin (\frac{2 \pi}{365}*7 -C) + 21.5

29= 7.5 sin (\frac{14 \pi}{365} -C) + 21.5

\frac{29-21.5}{7.5}=  sin (\frac{14 \pi}{365} -C)

1=  sin (\frac{14 \pi}{365} -C)

sin^{-1}(1)=   (\frac{14 \pi}{365} -C)

\frac{\pi}{2}=   (\frac{14 \pi}{365} -C)

C=   (\frac{14 \pi}{365} -\frac{\pi}{2})

C=   (\frac{28 \pi- 365 \pi}{730} )

C=  \frac{-337 \pi}{730}

Thus; the trigonometric function is;

y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5

Similarly; to determine the temperature o Jan 31; i.e when t= 31 ; we have :

y = 7.5 sin ( \frac{2 \pi}{365}*31+ \frac{337 \pi}{730})+ 21.5

y = 7.5 sin ( \frac{62 \pi}{365}+ \frac{337 \pi}{730})+ 21.5

y = 7.5 sin ( \frac{124 \pi+ 337 \pi }{730})+ 21.5

y = 7.5 sin ( \frac{461 \pi }{730})+ 21.5

y = 7.5 *( 0.915)+ 21.5

y = 6.8689+ 21.5

y = 28.36^0 \ C    ( to two decimal places)

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3 years ago
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Where’s the Picture of the cone
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