For f(x), 6 represents x here, so we plug 6 in for x to get 2*6²+5√(6-2). Using PEMDAS, we get 72+5√4=72+5*2=72+10=82
Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Ones and tens thats the anwers
Answer:
45?
Step-by-step explanation:
The perimeter is just the sum of all of the outside edges
So, the perimeter is (2*14)+(2*7), or 28+14, or 42
So the perimeter of figure 1, with all of the information that you have given me, is 42 units