5th term in expansion of (x-2)^7
1 answer:
Answer:
560x^3
Step-by-step explanation:
The formula is
(r + 1)th term of (a + x)^n = nCr a^(n-r)x^r
So 5th term = (4 + 1)th term
= 7C4 x^(7-4) (-2)^4
= 35x^3*16
= 560x^3
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