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galina1969 [7]
3 years ago
5

5th term in expansion of (x-2)^7

Mathematics
1 answer:
jeka943 years ago
7 0

Answer:

560x^3

Step-by-step explanation:

The formula is

(r + 1)th term of (a + x)^n = nCr a^(n-r)x^r

So 5th term = (4 + 1)th term

= 7C4 x^(7-4) (-2)^4

=  35x^3*16

= 560x^3

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