3 years ago

5th term in expansion of (x-2)^7

Mathematics

1 answer:

jeka943 years ago

7 0

Answer:

560x^3

Step-by-step explanation:

The formula is

(r + 1)th term of (a + x)^n = nCr a^(n-r)x^r

So 5th term = (4 + 1)th term

= 7C4 x^(7-4) (-2)^4

= 35x^3*16

= 560x^3

You might be interested in

Alyssa wants to tile a room with an área of 480 square feet.The width of the room is 12 feet.What is the length of the room?

AfilCa [17]

Answer:

Step-by-step explanation:

You do 480 divided by 12

3 0

3 years ago

Can someone please help me on this

Tanzania [10]

$a=2(-2)-1 = -4-1 =-5\\\\b=2(-1)-1 = -2 - 1 = -3\\\\c=2(1)-1 = 2-1 = 1\\\\d=2(2) -1 = 4 -1 =3$

7 0

2 years ago

How do you solve 8/11(n-10)=64

krek1111 [17]

Answer:

n = 98

Step-by-step explanation:

8/11 x (n - 10) = 64

multiply both sides of the equation by 11/8

11/8 x 8/11 x (n-10) = 11/8 x 64

reduce the numbers with greatest common divisor 11

1/8 x 8 (n-10) = 11/8 x 64

n - 10 = 11 x 8

multiply the numbers

n - 10 = 88

so then you add the numbers

n = 88 + 10

n= 98

6 0

3 years ago

Please help asap thank you

olga nikolaevna [1]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

2/5 + (5^2-10) / 5^2

Vadim26 [7]

$\bf \cfrac{2}{5}+\cfrac{5^2-10}{5^2}\implies \cfrac{2}{5}+\cfrac{~~\begin{matrix} 5^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} 5^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}-\cfrac{10}{5^2}\implies \cfrac{2}{5}+1-\cfrac{10}{25}\implies \cfrac{2}{5}+1-\cfrac{2}{5}\implies 1$

4 0

4 years ago