3 years ago

10x-35+3ax=5ax-7a solve for "a" for which the equation is an identity.

2 answers:

8 0

$10x-35+3ax=5ax-7a \\\\ 3ax-5ax+7a = -10x+35 \\\\ -2ax+7a = -10x+35 \\\\ a(-2x+7)=-10x+35 \\\\ a= \frac{-10x+35}{-2x+7} \\\\ a = \frac{5(-2x+7)}{(-2x+7)} \\\\ a=5$

ella [17]3 years ago

6 0

You can solve it by using PEMDAS

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Answer:

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Step-by-step explanation:

step 1

Find the surface area

we know that

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substitute

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substitute the approximate value of pi (3.14)

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step 2

Find the volume

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substitute

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riadik2000 [5.3K]

Answer:

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Step-by-step explanation:

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Solution

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3 years ago

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Step-by-step explanation:

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