3 years ago

10x-35+3ax=5ax-7a solve for "a" for which the equation is an identity.

2 answers:

8 0

$10x-35+3ax=5ax-7a \\\\ 3ax-5ax+7a = -10x+35 \\\\ -2ax+7a = -10x+35 \\\\ a(-2x+7)=-10x+35 \\\\ a= \frac{-10x+35}{-2x+7} \\\\ a = \frac{5(-2x+7)}{(-2x+7)} \\\\ a=5$

ella [17]3 years ago

6 0

You can solve it by using PEMDAS

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