Answer:
<em>95% for the true average increase in total cholesterol under these circumstances</em>
<em>(-2.306 , 9.406)</em>
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given sample size 'n' =41
Mean of the sample(x⁻) = 3.55
The estimated standard error

<em>Given estimated standard error ( S.E) = 3.478</em>
<em>Level of significance ∝=0.05</em>
<u><em>Step(ii)</em></u><em>:-</em>
<em>95% for the true average increase in total cholesterol under these circumstances</em>
<em></em>
<em></em>
<em>Degrees of freedom </em>
ν= n-1 = 41-1 =40
t₀.₀₅ = 1.6839
<em>95% for the true average increase in total cholesterol under these circumstances</em>
<em></em>
<em></em>
( 3.55 - 1.6839 ×3.478 ,3.55 + 1.6839 ×3.478 )
<em>(3.55 - 5.856 , 3.55 + 5.856)</em>
<em>(-2.306 , 9.406)</em>
<u><em>Conclusion:</em></u><em>-</em>
<em>95% for the true average increase in total cholesterol under these circumstances</em>
<em>(-2.306 , 9.406)</em>