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2 years ago

How do you do this question?

Mathematics

1 answer:

mr_godi [17]2 years ago

5 0

Answer:

None of the above

Step-by-step explanation:

According to the divergence test, if the limit of a sequence as n approaches infinity does not equal 0, then the series diverges. (Notice that if the limit does equal 0, the series doesn't necessarily converge).

According to the geometric series test, a geometric series converges if -1 < r < 1, and diverges otherwise.

The first series is a geometric series with r = -5/3. So it diverges.

The second series is also a geometric series:

3ⁿ⁻¹ / 2ⁿ = ⅓ (3ⁿ / 2ⁿ) = ⅓ (3/2)ⁿ

r = 3/2, so it diverges.

For the third series, the limit as n approaches infinity equals 1. This fails the divergence test, so this series also diverges.

For the fourth series, the limit as n approaches infinity equals 1. This fails the divergence test, so this series also diverges.

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Type the correct answer in the box

TiliK225 [7]

The expression of X in terms of l is X = √5 l

<h3>How to calculate the diagonal of a rectangle</h3>

According to the given information:

Length = w
If length<u> l is twice as long </u>as the width, then l = 2w

Determine the diagonal using the Pythagoras theorem:

X² = w²+(2w)²
X² = w² + 4w²

X =√5w²
X = √5 w

Replace w with l

X = √5 l

Hence the expression of X in terms of l is X = √5 l

Learn more on diagonals here: brainly.com/question/26154016

5 0

2 years ago

A. Sam purchased 3 games for $140 after a discount of 30%. What was the original price?

Semmy [17]

Answer:

a) $175 b) It will be $126

Step-by-step explanation:

Cost price of 3 games= $140

Let the original price of games= $ x

Discount is given= 30%

According to question

x $\frac{(100-20)}{100}$ = $140

x $\frac{80}{100}$ = $140

x ×0.8= $140

x= $ $\frac{$140}{0.8}$

x= $175

Hence, the original price of games $ 140

(b) If Sam had given a discount of 20%

Again a discount = 10%

The price of games=$ 140

Now, the selling price will be= 175 $\frac{(100-20)}{100}$ × $\frac{(100-10)}{100}$

Now, the selling price will be= $ 126

Hence, the price will be different.

7 0

3 years ago

2.1 km =

likoan [24]

2,100,000 Centimeters

3 0

2 years ago

Write an algebraic expression for the verbal description. the sum of two consecutive natural numbers, the first of which is n

scoundrel [369]

I think it may be:

n + (n + 1)

hope this helps

8 0

3 years ago

Read 2 more answers

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

$P(X \ge 1) = 0.509$

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$