suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
Given:
The given sequence is:

To find:
The recursive formula for
, the nth term of the sequence.
Solution:
We have,

Here, the first term is 5.



The common difference is -7.
The recursive formula for the nth term of the sequence is

Where,
is the common difference.
Putting
in the above formula, we get


Therefore, the recursive formula for the nth term of the sequence is
.
90 tens hopefully this helped