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2 years ago

13

Solve the following problems. Remember, it’s easiest to solve the questions in the parentheses first. a. 4 + (5+12) b. (3 + 6) +

17 c. (3 + 4) + (5 + 6) d. 9 + (11 + 7) + 10

2 answers:

Dmitry [639]2 years ago

4 0

Answer: The required answers are :

(a) 21, (b) 26, (c) 18 and (d) 37.

Step-by-step explanation: We are given to solve the following problems with parentheses solved first.

(a). The given problem is

$4+(5+12).$

We have

$4+(5+12)=4+17=21.$

(b) The given problem is

$(3+6)+17.$

We have

$(3+6)+17=9+17=26.$

(c) The given problem is

$4+(5+12).$

We have

$(3+4)+(5+6)=7+11=18.$

(d) The given problem is

$9+(11+7)+10.$

We have

$9+(11+7)+10=9+18+10=9+28=37.$

Thus, the required answers are :

(a) 21, (b) 26, (c) 18 and (d) 37.

galben [10]2 years ago

3 0

a. 21, b. 26, c. 18, d. 28

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Answer:

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<em>4)</em> $9d - 5 = 4$

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$= > 9d = 9$

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$= > \frac{9d}{9} = \frac{9}{9}$

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