Solve the following problems. Remember, it’s easiest to solve the questions in the parentheses first. a. 4 + (5+12) b. (3 + 6) +
2 answers:
Answer: The required answers are :
(a) 21, (b) 26, (c) 18 and (d) 37.
Step-by-step explanation: We are given to solve the following problems with parentheses solved first.
(a). The given problem is
We have
(b) The given problem is
We have
(c) The given problem is
We have
(d) The given problem is
We have
Thus, the required answers are :
(a) 21, (b) 26, (c) 18 and (d) 37.
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We use quadratic formula for that one
remember that √-1=i
so
for
ax^2+bx+c=0
so
given
5x^2-6x+2=0
a=5
b=-6
c=2
remember that √-1=i
so
for
ax^2+bx+c=0
so
given
5x^2-6x+2=0
a=5
b=-6
c=2
Answer: The correct option is
(D) 60.
Step-by-step explanation: Given that the number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively.
After Kaye gave Alberto 10 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 7:5.
We are to find the number of stamps that Kaye had more than Alberto.
Let the number of stamps Kaye and Alberto has are 5x and 3x respectively.
Then, according to the given information, we have
So, the number of stamps that Kaye had = 5 × 30 = 150
and
the number of stamps that Alberto had = 3 × 30 = 90.
Therefore, the number of stamps that Kaye had more than Alberto is
Thus, Kaye had 60 stamps more than Alberto.
Option (D) is CORRECT.