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V125BC [204]
2 years ago
7

What is the solution set for the inequality?

Mathematics
2 answers:
Slav-nsk [51]2 years ago
8 0

Answer: I say that the answer is D

Step-by-step explanation:

VARVARA [1.3K]2 years ago
6 0
Find out what x equals too
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<img src="https://tex.z-dn.net/?f=2x%20%7B%7D%5E%7B2%7D%20%20%2B%204x%20-%2021%20%3D%200" id="TexFormula1" title="2x {}^{2} + 4
Ugo [173]
The answer should be  21/8 hope it helps

7 0
3 years ago
Two​ shooters, Rodney and​ Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark
Sedaia [141]

Complete Question

Answer:

a

  SE  = 0.66}

b

-3.29 <  \mu_1 - \mu_2 <  -0.70  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  = 60

   The first sample mean is  \= x _1  =  8

    The second sample mean is   \= x _2  =  10

    The first variance is  v_1 =  0.25

    The first variance is  v_2 =  0.55

Given that  the confidence level is 95% then the level of significance is 5% =  0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the first standard deviation is  

     \sigma_1 =  \sqrt{v_1}

=>   \sigma_1 =  \sqrt{0.25}

=>   \sigma_1 =  0.5

Generally the second standard deviation is

     \sigma_2 =  \sqrt{v_2}

=>   \sigma_2 =  \sqrt{0.55}

=>   \sigma_2 =  0.742    

Generally the first standard error is

     SE_1  =  \frac{\sigma_1}{\sqrt{n} }

      SE_1  =  \frac{0.5}{\sqrt{60} }

     SE_1  =  0.06

Generally the second standard error is

     SE_2  =  \frac{\sigma_2}{\sqrt{n} }

      SE_2  =  \frac{0.742}{\sqrt{60} }

     SE_2  =  0.09

Generally the standard error of the difference between their mean scores is mathematically represented as    

      SE  =  \sqrt{SE_1^2 + SE_2^2 }

=>     SE  =  \sqrt{0.06^2 +0.09^2 }

=>     SE  = 0.66}

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } *  SE) <  \mu_1 - \mu_2 <  (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } *  SE)

=> (8 -10) -(1.96 *  0.66) <  \mu_1 - \mu_2 <  (8-10) +(Z_{\frac{\alpha }{2} } *  0.66)  

=>  -3.29 <  \mu_1 - \mu_2 <  -0.70  

 

5 0
3 years ago
Olympia ate lunch at a restaurant. The amount of her check was $6.89. She left $8.00 on the table, which included the amount she
Stolb23 [73]
<span>6.89 + t = 8.00</span><span>
t = 8 - 6.89
t = 1.11

tips = $1.11

</span>answer

a.6.89 + t = 8.00
8 0
3 years ago
Read 2 more answers
Triple a number, minus the sum of the number and six
9966 [12]

\large \mathfrak{Solution : }

let the number be x

According to above statement :

  • 3x - (x + 6)

  • 3x - x - 6

  • 2x - 6

6 0
2 years ago
Read 2 more answers
I have 12 apples, but I take 2, 3 are molding, 1 has a worm in it, I'm eating 1, and 3 fell on the floor... how much apples do I
solong [7]

Answer:

12 counting the one you're eating

Step-by-step explanation:

8 0
2 years ago
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