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Hoochie [10]
3 years ago
7

The figure below shows a rectangle ABCD having diagonals AC and DB:

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0

Answer: C is the correct statement " In ΔADC and ΔBCD AD=BC, opposite sides of  a rectangle are congruent"which completes the proof .


Step-by-step explanation:

Given: A figure shows a rectangle ABCD having diagonals AC and DB.

Anastasia wrote the  proof  given in picture to show that diagonals of rectangle ABCD are congruent.

We can see the Statement 2 which tells that AB=CD, opposite sides of  a rectangle are congruent. In Statement 3 she used Pythagoras theorem to show AC²= BD² by using Statement 1 and 2.

Thus we can see she need to introduce two triangles named as ACD and BCD and the remaining sides to write the proof is AD=BC with correct reason i.e. opposite sides of  a rectangle are congruent.

Therefore Statement 1 would be In ΔADC and ΔBCD AD=BC, opposite sides of  a rectangle are congruent.


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