Solve for x please thanks

I rlly need to know this asap thanks

dusya [7]

= 6g - 24 + 7g +4
= 13g - 20

3 0

3 years ago

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Which shows the following expression after the negative exponents have been eliminated?

belka [17]

Answer:

The given expression $\frac{a^3}{ab^{-4}}$ after the negative exponents have been eliminated becomes $\frac{a^3b^{4}}{ab^{2}}$

Step-by-step explanation:

Given expression $\frac{a^3b^{-2}}{ab^{-4}}$

We have to write expression after the negative exponents have been eliminated and a ≠ 0 and b ≠ 0.

Consider the given expression $\frac{a^3b^{-2}}{ab^{-4}}$

We have to eliminate the negative exponents,

Using property of exponents, $x^{-m}=\frac{1}{x^m}$ we have ,

$b^{-2}=\frac{1}{b^2} \\\\b^{-4}=\frac{1}{b^4}$

Substitute, we get,

$\frac{a^3}{ab^{-4}}$ becomes $\frac{a^3b^{4}}{ab^{2}}$

Thus, the given expression $\frac{a^3}{ab^{-4}}$ after the negative exponents have been eliminated becomes $\frac{a^3b^{4}}{ab^{2}}$

5 0

3 years ago

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Give the excluded values for the rational equation. (3x)/(x-4)-(x+3)/(x+4)=(2x+7)/(x^(2)-16)

scoray [572]

$\frac{3x}{x-4} - \frac{x+3}{x-4} = \frac{2x+7}{x^2-16}$

We factor the denominators

Factor x^2 - 16

x^2 - 4^2

We use a^2 - b^2 = (a+b)(a-b)

so x^2 - 4^2 = (x+4)(x-4)

Replace it in the given equation

$\frac{3x}{x-4} - \frac{x+3}{x-4} = \frac{2x+7}{(x+4)(x-4)}$

Excluded values are the values that makes the denominator 0

we have (x-4) and (x+4) in the denominator

We set the denominator =0 and solve for x

x-4 =0

Add 4 on both sides

x= 4

x+4=0

subtract 4 onboth side

so x= -4

Excluded values are x=-4 and x=4

8 0

3 years ago

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Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm prett

valentinak56 [21]

Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

With 5 shoots, the probability of making at least one is $\frac{211}{243}$ , hence the probability of making none, P(X = 0), is $\frac{232}{243}$ , hence:

$(1 - p)^5 = \frac{232}{243}$

$\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}$

1 - p = 0.9908

p = 0.0092

Then, with 6 shoots, the parameters are:

n = 6, p = 0.0092.

The probability that at least two of them make it inside the recycling bin is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

[P(X < 2) = P(X = 0) + P(X = 1)

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461$

$P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527$

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012$

0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

7 0

2 years ago

What are the properties of rotations?

11Alexandr11 [23.1K]

Rotations move lines to lines, rays to rays, segments tosegments, angles to angles, and parallel lines to parallel lines, similar to translations and reflections. Rotations preservelengths of segments and degrees of measures of anglessimilar to translations and reflections.

6 0

3 years ago

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