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never [62]
3 years ago
13

Find the center and the radius of the circle with the equation: x^2-4x+y^2

Mathematics
1 answer:
zysi [14]3 years ago
8 0

Answer:

Step-by-step explanation:

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Write the point-slope equation of the line that goes through (1, 4) with a slope of -10
sammy [17]

Answer:

y-4=-10(x-1)

Step-by-step explanation:

Point-slope form is:

y-y_1=m(x-x_1)\\m-slope\\(x_1,y_1)-point

We are given the slope of -10 and the point (1,4). So:

m = -10

x1 = 1

y1= 4

Replace the appropriate values:

y-4=-10(x-1)

So, y-4=-10(x-1) should be the point-slope equation.

3 0
2 years ago
Read 2 more answers
Which input is incorrect
Sladkaya [172]
The answer you are looking for is A. 7.00. The cost of the item should be $6.00 as the tax should be $0.48. Making the total cost of the item $6.48.
7 0
3 years ago
2. Sandra plans to swim a total of 2 2/3 miles every week for 2 1/5
Fed [463]

Answer:

5 13/15 miles

Step-by-step explanation:

3 0
2 years ago
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
2 years ago
Solve the system 2x-2y=10 4x-5y=17
stiv31 [10]
Multiply 2x-2y=10 by 2,
4x-4y=20,
given:4x-5y=17
y=3
pluck it in
2x-6=10
move the 6 to the right
2x=16
divide
x=8
y=3
8 0
3 years ago
Read 2 more answers
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