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AysviL [449]
4 years ago
9

At the movie theatre, child admission is $5.70 and adult admission is $9.75 . On Friday, 173 tickets were sold for a total sales

of 1306.10 . How many child tickets were sold that day?
Mathematics
1 answer:
storchak [24]4 years ago
7 0

Answer: 94 child tickets

<u>Step-by-step explanation:</u>

Let x represent child tickets

Let y represent adult tickets

Cost Equation: 5.70x + 9.75y = 1306.10

Quantity Equation: x + y = 173

Solve the system of equations using the elimination method:

Multiply the Quantity Equation by -5.70

      5.70x + 9.75y = 1306.10

    <u> -5.70x  - 5.70y</u> = <u>-986.10</u>

                    4.05y = 320.00

                  <u> ÷4.05 </u>   <u>÷4.05    </u>

                           y =   79

x +  y  = 173

x + 79 = 173

x         = 94

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Answer:

The 85% confidence interval for the population proportion that claim to always buckle up is (0.7877, 0.8441).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

They randomly survey 391 drivers and find that 319 claim to always buckle up.

This means that n = 391, \pi = \frac{319}{391} = 0.8159

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8159 - 1.44\sqrt{\frac{0.8159*0.1841}{391}} = 0.7877

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8159 + 1.44\sqrt{\frac{0.8159*0.1841}{391}} = 0.8441

The 85% confidence interval for the population proportion that claim to always buckle up is (0.7877, 0.8441).

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3 years ago
In how many ways can 5 men and 5 woman sit alternately in a row of 10 seats?
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so (5*4*3*2) = 120

120 *120 = 14,400 ways



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3 years ago
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