Answer:
length = 60 foot, width = 30 foot
Step-by-step explanation:
Area of rectangular part, A = 1800 ft²
Cost of fencing three sides is $ 6 per foot and cost of one side fencing is $18 per foot.
Let the length of the rectangle is l and the width of the rectangle is W.
Area = Length x width
A = L x W
1800 = L x W ...... (1)
Total cost of fencing, C = 6 x ( L + W + L) + 18 x W
C = 6 (2L + W) + 18 W
C = 12 L + 24 W
Substitute the value of W from equation (1),
in equation (2)


Differentiate both sides with respect to L:

Put it equal to zero for maxima and minima

L = 60 foot
and W = 30 foot
So, the costing is minimum for length = 60 foot and the width = 30 foot.
(13-2x)(13-2x)
(13+-2x)(13+-2x)
(13)(13)+(13)(-2x)+(-2x)(13)+(-2x)(-2x)
169-26x-26x+4x^2
4x^2-52x+169
I hope that's help !
I
Answer: You can use only common factor (3).
Step-by-step explanation:
12g²-27h²
3 . ( 4g² - 9h² )
278. I got It By Counting The Letters On Meh Keyboard As Many Times As The #'s On My Keyboard.