Seventeen people have been exposed to a particular disease. Each one independently has a 40% chance of contracting the disease.
A hospital has the capacity to handle 10 cases of the disease. What is the probability that the hospital's capacity will be exceeded?
(a) 0.011
(b) 0.035
(c) 0.092
(d) 0.965
(e) 0.989
(a) 0.011
(b) 0.035
(c) 0.092
(d) 0.965
(e) 0.989
1 answer:
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The answer is 34.05
The total distance (D) is the sum of three distances (d1, d2, and d3).
The distance formula is
Distance 1: Phoenix (–12, –16) to Blythe (–20, –9)<span>:
</span>
Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
Distance 3: Los Angeles (–33, –4) to <span>San Francisco (–36, 5)
</span>
<span>
D = d1 + d2 + d3 = 10.63 + 13.93 + 9.49 = 34.05</span>
The total distance (D) is the sum of three distances (d1, d2, and d3).
The distance formula is
Distance 1: Phoenix (–12, –16) to Blythe (–20, –9)<span>:
</span>
Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
Distance 3: Los Angeles (–33, –4) to <span>San Francisco (–36, 5)
</span>
<span>
D = d1 + d2 + d3 = 10.63 + 13.93 + 9.49 = 34.05</span>