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Rama09 [41]
2 years ago
9

How would you do this problem 1/4 (8-6x+20)

Mathematics
2 answers:
Volgvan2 years ago
7 0
So to do this question, first rearrange the numerals n the parenthesis.

\frac{1}{4} (8 + 20 - 6x)
\frac{1}{4} (28 - 6x)

Now, distribute the \frac{1}{4} into the parenthesis.
\frac{28}{4} - \frac{6x}{4}
7 - \frac{6x}{4}

- \frac{6x}{4} = -1.5x

7 - 1.5x
den301095 [7]2 years ago
4 0
Distribute 1/4 by multiplying it by 8, -6X and 20 you end up with 
1/4times8=2
1/4times-6x= -1.5x
1/4times20=5
so 2-1.5x+5
add 2 and 5 to get 7
the answer is -1.5x+7
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What is the common ratio of 17, 51, 153, 459,.....
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Answer:

3

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17 * 3 = 51

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153 * 3 = 459

etc.

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2 years ago
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Please help and with explanation
Zanzabum

Answer:

x=-1

Step-by-step explanation:

STEP 1: Factor  x ^2 − 8 x + 12  using the AC method.

\frac{4}{(x-6)(x-2)} =\frac{x}{x-2} +\frac{1}{x-6}

STEP 2: Find the LCD of the terms in the equation.

(x-6)(x-2)

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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

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at t = 0, x = 1

y = e^(-5t)sin5t

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at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

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r(t) = xi + yj + zk

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is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

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3 years ago
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