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hjlf
3 years ago
6

The function h is defined by h (y) = 2y-7. What is the value of h(8) ? ooo

Mathematics
1 answer:
kozerog [31]3 years ago
6 0

Answer:

The value of h(8) = 9  

Step-by-step explanation:

Given function as

h(y) = 2y - 7

For y = 8

Put the value of y in given function

So, h(8) = 2 (8) - 7

OR , h(8) = 16 - 7

∴  h(8) = 9  

Hence the value of h(8) = 9    Answer

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Step-by-step explanation:

Given:

The given factor is.

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We need to find the factors of given factor.

Solution:

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Now we factorised the above equation.

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Now we substitute (x+2)(x-12) in the place of x^{2} -10x-24

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f(x)=x(x^{2}-4)+(x+2)(x-12)

Simplify x^{2} -4=x^{2} -(2)^{2} = (x+2)(x-2)

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Common factor for above function (x+2)

f(x)=(x+2)[x(x-2)+(x-12)]

Simplify.

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So the factors of the function.

f(x)=(x+2)(x-4)(x+3)

Therefore, the factors of the given function are (x+2)(x-4)(x+3)

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