3u^2+8u-3
with grouping, we have to find 2 numbers which add up to 8 and multiply to 3*(-3)= -9.
testing, we find that 9 and -1 add up to 8 and multiply to -9.
so now we can write the original equation as
3u^2-u+9u-3
you can factor the terms in pairs:
u(3u-1)+3(3u-1)=
(u+3)(3u-1)
As far as steps i’ll tell you in the comments
Answer:
Hope this helped.
A brainliest is always appreciated.
Answer:
2^0+2^1+2^2+...+2^49
Step-by-step explanation:
1=2^0
2=2^1
4=2^2
8=2^3
and so on
