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jeka94
3 years ago
14

Xis all of the following except

Mathematics
2 answers:
bixtya [17]3 years ago
5 0

Answer:

a variable

Step-by-step explanation:

a variable.

11Alexandr11 [23.1K]3 years ago
5 0
X is not an expression unless it has signs. so x by itself would not be an expression without different numbers and sign between
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Help me in my math thank you​
Vlad [161]

Answer:

For question 1 it's 12/3

For question 2 it's D. 6

For question 3 it's A. 12

For question 4 it's C. 64

For question 5 it's D. 1 and 17/18

For question 6 it's B. 16

Step-by-step explanation:

All answers are correct, trust me. I put my time into this. I hope you get a good grade and you have an amazing day! ❤

5 0
3 years ago
Read 2 more answers
Katie said,"Negative numbers are integers."What was her error?
lubasha [3.4K]
<span>Katie has not made an error. Negative numbers are integers, along with whole numbers. Whole numbers are the natural numbers (1, 2, 3 and so on) and 0.</span>
6 0
4 years ago
Does the order matter when rotating an image?
xz_007 [3.2K]

Answer:

the order is important when you are performing a composite transformation

4 0
3 years ago
If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
Vesna [10]

Answer:

8 units

Step-by-step explanation:

Hello!

So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that  c = \sqrt{{a}^2 + b^{2} }, where <em>c</em> is the hypotenuse and <em>a</em> and <em>b </em>are the legs of the triangle.

So, from the problem,  if <em>c </em>= 17 and <em>a </em> = 15, then, we're solving for <em>b</em>. So we'll rewrite the theorem to solve for <em>b</em>.

{c}^2 = {a}^2+{b}^2\\{c}^2-{a}^2={b}^2\\{b} = \sqrt{{c}^2-{a}^2}

Okay, so now we have isolated the theorem for <em>b. Let's </em>plug in our values for <em>c </em>and <em>a</em>.

b = \sqrt{{17}^2-{15}^2}\\b = \sqrt{289-225}\\b = \sqrt{64}\\b = 8

So, using the theorem, we found <em>b</em> = 8. To check our work, let's plug in <em>b</em> and <em>a</em> and solve for <em>c.</em>

<em />c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\<em />

So, we got our hypotenuse to equal 17 units, which is correct! So, our <em>b</em> is correct too. Awesome

7 0
3 years ago
5x-4x+3=4x-12<br> A)4<br> B)5<br> C)-5<br> D)-4
slavikrds [6]

Answer:

B.) 5

Hope this helps :)

Step-by-step explanation:

5x - 4x + 3 = 4x - 12

x + 3 = 4x - 12

 +12               +12

x + 15 = 4x

-x         -x

15 = 3x

x = 5

6 0
3 years ago
Read 2 more answers
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