Answer:
k=2
Problem:
if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is ..
Step-by-step explanation:
Since the coefficient of x^2 is 1, we can use this identity to aid us: x^2+bx+(b/2)^2=(x+b/2)^2.
So we want the following:
[(k+2)/2]^2=2k
Apply the power on the left:
(k+2)^2/4=2k
Multiply both sides by 4:
(k+2)^2=8k
Expand left side:
k^2+4k+4=8k *I used identity (x+c)^2=x^2+2xc+c^2
Subtract 8k on both sides:
k^2-4k+4=0
Factor using the identity mentioned a couple lines above:
(k-2)^2=0
Since zero squared is zero, we want k-2=0.
Adding both sides by 2 gives k=2.
She has a choice of 6 outfits to coordinate for the day
<h3>
Answer: y = -2</h3>
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Work Shown:
m = 0 is the slope
b = -2 is the y intercept
y = mx+b
y = 0x+(-2)
y = 0x-2
y = 0-2
y = -2
This line is horizontal and goes through -2 on the y axis.
Two points on this line are (0,-2) and (1,-2)
Answer:
-3.25
Step-by-step explanation:
