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jek_recluse [69]
3 years ago
5

Solve the equation below using elimination*

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer:

x=2

y=−1

Step-by-step explanation:

You can multiply the second equation by 3:

{2x-3y=7

{9x+3y=15 add the two together (in columns):

11x+0=22

so that x=22/11=2

substitute this back into the first equation:

2*2-3y=7

y=-1

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What is a correlation
posledela

Answer: a relationship/connection between two variables, there are negative and positive correlations.

7 0
3 years ago
Express the following as powers of 64: (e) 1 (f) 1/64 (g) 1/8 (h) 1/2 (I) 1/64
____ [38]

Answer:

(e) 1 =64⁰

(f) 1/64 = 64⁻¹ negative one power

(g) 1/8 = 64⁻¹/² negative one half power

(h) 1/2 = 64⁻1/6 negative one/sixth power

(I) 1/64 same as (f) ??

Step-by-step explanation:

6 0
3 years ago
Solve 4x−5=7+4y for y.
drek231 [11]

4x−5=7+4y

subtract 7 from both side

4x - 5 -7 = 4y

4x -12 = 4y

divide by 4

4x/4 -12/4 = 4y/4

x-3=y

6 0
3 years ago
Read 2 more answers
PLZZZZZ HELPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
shtirl [24]

Answer:

y = 3

x = 1

y = 1.5

x = 2

Step-by-step explanation:

For the first x point, look at the graph where x is 0. When x is 0, y is 3. So the first one is 3. For the second one, there is a point on the graph where y is 4. Where y is 4, x is 1, so you the second answer is 1. For the third one, find the y point where x is -1. At the x value, -1, y is 1.5. For the last one, where y is 5, x is 2.

8 0
2 years ago
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A manufactured product has a length that is normally distributed with a mean of 12 cm. The product will be unusable if the lengt
Sav [38]

Answer:

a) σ  = 0,1612

b) P [ 11,75 < X < 12,35] = 0,92,44   or    92,44 %

Step-by-step explanation:

NOTE: I assume the unusable length s 11,5 and less

a) For a normal distribution, the probability of P = 0,01 corresponds to z(score) =  -3,1 then:

- 3,1 = ( X - μ₀ ) / σ

- 3,1 = (11,5 - 12 )/ σ

-3,1 = - 0,5 / σ

σ  = 0,1612

b) If σ = 0,1612

P [ 11,75 < X < 12,35]

z₁ (score)  = ( 11,75 - 12 ) / 0,1612

z₁  = - 0,25/ 0,1612

z₁  = -1,55

From z table  P [ 11,75 < X] = 0,0606

z₂ (score) = ( 12,35 - 12) / 0,1612

z₂ = 0,35 / 01612

z₂ = 2,17

From z table  P [ X < 12,35] = 0,9850

Finally P [ 11,75 < X < 12,35] = 0,9850 -  0,0606

P [ 11,75 < X < 12,35] = 0,92,44   or    92,44 %

5 0
3 years ago
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