Answer:
m∠CAO=8º
m∠SAC=82º
Step-by-step explanation:
We know that m∠OAS is 90º because it is a radius to a tangent. This will be useful later.
OA=OB because they are both radii. If we draw a line from A to B, this makes an isosceles triangle ABO with a vertex angle of 32 because of the central angle theorem. This means that m∠OAB and m∠OBA are both 74º.
Isosceles triangle CAB is also formed with the construction of AB. Using the inscribed angle theorem, we can find ACB, which is 16º. Solve for the other angles and you get 82º. To find m∠CAO, subtract m∠OAB from m∠CAB, and this returns 8.
To find m∠SAC, subtract m∠CAO from m∠OAS, which is 90º-8º, and you get 82º.
Answer: he sent 574 text messages that month
Step-by-step explanation:
Let x represent the number additional text messages that he sent that month.
If his text messaging complain cost $9 for the first 550 text messages and .20 for additional text messages, it means that the total cost of sending x text messages for a month would be
9 + 0.2(x - 550)
If Tj owes $13.80 for text messaging in the month of March, it means that
9 + 0.2(x - 550) = 13.8
0.2x - 110 = 13.8 - 9
0.2x = 13.8 - 9 + 110
0.2x = 114.8
x = 118.8/0.2
x = 574
Answer:
12.57
Step-by-step explanation:
C=2πr
2π2
4π
12.57
So if the perimeters are equal then you know
Rectangle Triangle
x + x + x + 4 + x + 4 = x + x + 9 + x + 5
which becomes
4x + 8 = 3x + 14
now you can solve the equation for x, then find the perimeters
Vertices (3,0),(-3,0) co-vertices (0,-5),(0,5)
transverse axis (line passing vertices) is on(or parallel to) x-axis then formula is
(x-h)^2/a^2 - (y-k)^2/b^2 = 1
..notice.. x^2 is on positive / y^2 is on negative
center (h,k) is midway between vertices = (0,0)
we have h = k = 0 and now formula is
x^2/a^2 - y^2/b^2 = 1
a is the distance from a vertex to center = 3
b is the distance from a co-vertex to center = 5
the formula is
x^2/3^2 - y^2/5^2 = 1 ... answer is the 1st
