Answer:
m∠CAO=8º
m∠SAC=82º
Step-by-step explanation:
We know that m∠OAS is 90º because it is a radius to a tangent. This will be useful later.
OA=OB because they are both radii. If we draw a line from A to B, this makes an isosceles triangle ABO with a vertex angle of 32 because of the central angle theorem. This means that m∠OAB and m∠OBA are both 74º.
Isosceles triangle CAB is also formed with the construction of AB. Using the inscribed angle theorem, we can find ACB, which is 16º. Solve for the other angles and you get 82º. To find m∠CAO, subtract m∠OAB from m∠CAB, and this returns 8.
To find m∠SAC, subtract m∠CAO from m∠OAS, which is 90º-8º, and you get 82º.
