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Nikitich [7]
3 years ago
13

write your own problem that includes the number 1 million. Exchange your problem for that of a friend. Solve the problem you rec

eive. Can someone PLEASE give me good ideas for this!? I am not good at thinking :( it can’t be too simple by the way
Mathematics
2 answers:
Leni [432]3 years ago
7 0

Answer:

600,000 +400,000 = 1,000,000

Step-by-step explanation:

Just Add Hoped It Helped

Marysya12 [62]3 years ago
4 0

Answer:

I have 1 million dreams a year so on and so on

Step-by-step explanation:

You might be interested in
A missile protection system consists of n radar sets operating independently, each with probability 0.9 of detecting a missile e
stepladder [879]

Answer:

A.) The probability that the missile is not detected by any of n sets = (1-0.9)^n = 0.1^n.

Where it's opposite will be that the missile is detected by atleast 1 of the sets. Which will be equals to 1-(0.1)^n.

B.) 0.999= 1-(0.1)^n

Here n=3

For, 0.999999=1-(0.1)^n

n=6.

C.) If n=5

5C4*(0.9)^4*(0.1)^1= 0.32805

6 0
3 years ago
How do I solve this?
MrMuchimi

Answer:

X = 30 over 7

Step-by-step explanation:

multiply both sides of the equation by 6.

collect like terms.

divide both sides of the equation by 7.

solution should be

X = 30/7

5 0
3 years ago
Find the intersection of H and G find the union of H and G
ra1l [238]

H∩G={1,9} INTERSECTION OF H AND G

H∪G={1,2,3,5,6,7,9,10,11,28} UNION OF H AND G

<u>Step-by-step explanation:</u>

Step-1:  

Let H={1,2,5,7,9,10} and G={1,3,6,9,11,28} are individual set

Intersection of H and G (H∩G) is {1,9} Which means the COMMON ELEMENTS in both the set.

Step-2:

Now the Union in both the set (H AND G) (H∪G) is {1,2,3,5,6,7,9,10,11,28}.

Which means ALL THE ELEMENTS in both set.

5 0
3 years ago
For the past 40 days. Naomi has been recording the number of customers at her restaurant between 10:00 AM and 11:00 AM. During t
igor_vitrenko [27]

Answer:

The experimental probability there will be fewer than 20 customers on the forty-first day is 5/8, .625, 62.5%.

Step-by-step explanation

:


4 0
3 years ago
Rajan needs 1 liter of 15% hydrochloric acid solution for an experiment. He checks his storage cabinet, but he only has a 5-lite
yarga [219]

Answer:

<em>Rajan must use </em><em>0.75</em><em> liters of 5% hydrochloric acid solution and </em><em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>

Step-by-step explanation:

Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.

As Rajan need total of 1 liter of solution, so

x+y=1

i.e x=1-y --------------------1

As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

0.05x+0.45y=1\times 0.15

i.e 5x+45y=15 -------------2

Putting value of x from equation 1 in equation 2,

\Rightarrow 5(1-y)+45y=15

\Rightarrow 5-5y+45y=15

\Rightarrow 5+40y=15

\Rightarrow 40y=15-5=10

\Rightarrow y=0.25

Putting the value of y in equation 1,

x=1-0.25=0.75

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters of 45% hydrochloric acid solution.

5 0
4 years ago
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